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Ann [662]
3 years ago
8

Factoring quadratic expressions with leading coefficient 1

Mathematics
1 answer:
elena55 [62]3 years ago
7 0

Answer:

It is a letter with ^ before the expression.

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What is 200%of 4420​
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8,840

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Multiply 4420 by 200% to get the answer 8840. You can also multiply 4420 by 2 to get the same answer as you would multiplying by 200%.

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BRAINLIEST, 5 STARS, 50 POINTS AND THANKS IF ANSWERED CORRECTLY.
Troyanec [42]

Answer:

see explanation

Step-by-step explanation:

(1)

x² + 4 = 0 ( subtract 4 from both sides )

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Solve the equation for x. show each step of the solution. name the justification for each step of the solution. 9/2(8-x)+36=102-
sergij07 [2.7K]

The answer is  x= -10. To get this answer you have to simplify both sides of the equation, distribute, and combine the like terms. The second step is to add 15/2x to both sides. Step 3 is to subtract 72 from both sides, then divide both sides by 3


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Using the given definition and \Delta x=\frac{0-(-2)}n=\frac2n, we have

\displaystyle \int_{-2}^0 (7x^2+7x) \,dx = \lim_{n\to\infty} \sum_{i=1}^n \left(7\left(-2+\frac{2i}n\right)^2 + 7\left(-2+\frac{2i}n\right)\right) \frac2n \\\\ ~~~~~~~~ = \lim_{n\to\infty} \frac2n \sum_{i=1}^n \left(14 - \frac{42i}n + \frac{28i^2}{n^2}\right)

Recall the well-known power sum formulas,

\displaystyle \sum_{i=1}^n 1 = \underbrace{1 + 1 + 1 + \cdots + 1}_{n\,\rm times} = n

\displaystyle \sum_{i=1}^n i = 1 + 2 + 3 + \cdots + n = \frac{n(n+1)}2

\displaystyle \sum_{i=1}^n i^2 = 1 + 4 + 9 + \cdots + n^2 = \frac{n(n+1)(2n+1)}6

Reducing our sum leads to

\displaystyle \int_{-2}^0 (7x^2+7x) \,dx = \lim_{n\to\infty} \frac2n \left(\frac{7n}3 - 7 + \frac{14}{3n}\right) = \lim_{n\to\infty} \left(\frac{14}3 - \frac{14}n + \frac{28}{3n^2}\right)

As n goes to ∞, the rational terms containing n will converge to 0, and the definite integral converges to

\displaystyle \int_{-2}^0 (7x^2+7x) \,dx = \boxed{\frac{14}3}

3 0
2 years ago
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