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hjlf
3 years ago
6

-5,-6,0,6 which pair of numbers has a sum of zero

Mathematics
1 answer:
ladessa [460]3 years ago
7 0

Answer:

-6, 6

Step-by-step explanation:

I hope this helps :)

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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
svet-max [94.6K]

Answer:

tan (C) = 2.05

Step-by-step explanation:

Given:

A right angled triangle CDE right angled at ∠D.

Side CD = 39

Side DE = 80

Side CE = 89

We know, from trigonometric ratios that, the tangent of any angle is equal to the ratio of the opposite side to the angle and the adjacent side of the angle.

Therefore, tangent of angle C is given as:

\tan(\angle C)=\frac{DE}{CD}

Plug in the given values and solve for angle C.This gives,

\tan(\angle C)=\frac{80}{39}\\\\\tan(\angle C)=2.051\approx 2.05(Rounded\ to\ nearest\ hundredth)

Therefore, the measure of tangent of angle C is 2.05.

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2 years ago
A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

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2 years ago
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