Complete question :
A random sample of n = 83 measurements is drawn from a binomial population with probability of success 0.4 . Complete parts a through d below. a. Give the mean and standard deviation of the sampling distribution of the sample proportion, . The mean of the sampling distribution of is nothing. The standard deviation of the sampling distribution of is nothing.
Answer:
Mean = 33.2000
Standard deviation = 4.4632
Step-by-step explanation:
Given that :
Sample size (n) = 83
Probability of success (p) = 0.4
q = p' = (1 - p) = 1 - 0.4 = 0.6
The mean of the sampling distribution :
Sample size * probability of success
n * p = 83 * 0.4 = 33.2000
The standard deviation of the sampling distribution :
σ=√(sample size * probability of success * (1 - p))
σ = √n * p * (1 - p)
σ = √(83 * 0.4 * 0.6)
σ = √19.92
σ = 4.46318
σ = 4.4632
Answer:
B.
Step-by-step explanation:
The function is positive when it is above the x-axis
The following x values are where the function has positive y coordinates:
(-2,0)
(4,inf)
The function is negative when it is below the x-axis
The following x values are where the function has negative y coordinates:
(-inf,-2)
(0,4)
So you should see all of these intervals listed in choice B
Answer:
0.857 weeks
Step-by-step explanation:
Using the information provided we can create the following equations for the total amount Mallory (M) and Aimee (A) will save after x number of weeks...
M = 35 + 15x
A = 5 + 50x
Now we would need to make both of these equations equal one another and solve for x to calculate after how many week both Aimee and Mallory will have saved the same amount of money
35 + 15x = 5 + 50x ... subtract 5 and 15x from both sides
30 = 35x ... divide both sides by 35
or 0.857 = x
Finally, we can see that after 0.857 weeks both Mallory and Aimee will have saved the same amount of money.
*** The process provided is correct but I believe that the actual values for Aimees savings should be $50 and plans to save $5 a week, this would make the final result 1.5 weeks which would make more sense***
Using the probability table, it is found that:
- a) There is a 0.25 = 25% probability that this couple spends 45 dollars or more.
- b) The expected amount the couple actually has to pay is $36.85.
Item a:
To find the probabilities involving the total cost, we have to <u>add the variables X and Y</u> from the table, then:





The probability involving <u>values of 45 or more</u> is:

0.25 = 25% probability that this couple spends 45 dollars or more.
Item b:
For a <em>discrete distribution</em>, the expected value is the <u>sum of each outcome multiplied by it's respective probability</u>, hence, involving the 10% discount for prices above $45:
![E(X) = 0.2(30) + 0.3(35) + 0.25(40) + 0.9[0.2(45) + 0.05(50)] = 36.85](https://tex.z-dn.net/?f=E%28X%29%20%3D%200.2%2830%29%20%2B%200.3%2835%29%20%2B%200.25%2840%29%20%2B%200.9%5B0.2%2845%29%20%2B%200.05%2850%29%5D%20%3D%2036.85)
The expected amount the couple actually has to pay is $36.85
A similar problem is given at brainly.com/question/25782059