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1 year ago

How to solve 2a x a x a x3a + b +4b

Mathematics

2 answers:

laiz [17]1 year ago

4 0

$2a \cdot a \cdot a \cdot 3a +b+4b\\\\=6a^{1+1+1+1} +5b\\\\=6a^4 +5b$

kodGreya [7K]1 year ago

3 0

Answer:

$6 {a}^{4} + 5b$

Step-by-step explanation:

$2a \times a\times a \times 3 a+ b + 4b \\ 2a \times a = 2 {a}^{2} \\ 2 {a}^{2} \times a = 2 {a}^{3} \\ 2 {a}^{3} \times 3a = 6 {a}^{4} \\b + 4b = 5b$

Therefore the answer is

$6 {a}^{4} + 5b$

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Reptile [31]

Answer:

2nd one

Step-by-step explanation:

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2 years ago

Read 2 more answers

-3/v=-6 simply as much as possible

Aleksandr [31]

Hey!

In order to simplify this equation, we'll first have to multiply both sides of the equation by v. This will give us v on its own.

Original Equation :
$\frac{-3}{v} = -6$

New Equation {Added Multiply Both Sides by V} :
$\frac{-3}{v} v=-6v$

Solution {New Equation Solved} :
$-3 = -6v$

Now we'll switch sides to get v on the left side of the equation which is generally where we always want the variables to be located in these types of equations.

Old Equation :
$-3 = -6v$

New Equation {Switched} :
$-6v=-3$

Now we'll divide both sides by v to get v on its own.

Old Equation :
$-6v = -3$

New Equation {Added Divide Both Sides by V} :
$\frac{-6v}{v} = \frac{-3}{v}$

Solution {New Equation Solved} :
$v = \frac{1}{2}$

So, this means that in the equation $\frac{-3}{v} =-6$ , $v = \frac{1}{2}$ .

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- Lindsey Frazier ♥

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2 years ago

There are 81 red, blue and yellow

wel

Step-by-step explanation:

Here Given

Total counters = 81

red counters are 9 more than the yellow ones.

And Yellow counter = blue counter

So let the Yellow counter be x and as blue counter and yellow counter are same then blue counter will be also x

And by the question

Red counter = 9 + x

Now

9 + x + x + x = 81

9 + 3x = 81

3x = 81 - 9

3x = 72

x = 72 / 3

Therefore x = 24

Now

Red counters = 9 + 24 = 33

Blue counters = 24

Yellow counters = 24

Hope it helped :)

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2 years ago

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Aloiza [94]

It would surely be helpful if you let us know which angles to measure!

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