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3 years ago

13

Ms. Boehmer's dog Stella weighs about 20.5 kilograms. How many grams does it weigh?

2 answers:

Zarrin [17]3 years ago

8 0

Answer:

20500

Step-by-step explanation:

Every kilogram is 1000 grams,

You would times 20.5 by 1000 to get

20500 grams.

Ivahew [28]3 years ago

6 0

20500 because every kg are 1000

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13/14 make it in to a equivalent fraction

Reika [66]

Answer:

Equivalent fraction would be 26/28

Step-by-step explanation:

Just multiply the top and bottom by a # to get an equivalent fraction

5 0

3 years ago

A group of three undergraduate and five graduate students are available to fill certain student government posts. If four studen

creativ13 [48]

Answer:

$Pr = 0.4286$

Step-by-step explanation:

Given

Let

$U \to\\$ Undergraduates

$G \to$ Graduates

So, we have:

$U = 3; G =5$ -- Total students

$r = 4$ --- students to select

Required

$P(U =2)$

From the question, we understand that 2 undergraduates are to be selected; This means that 2 graduates are to be selected.

First, we calculate the total possible selection (using combination)

$^nC_r = \frac{n!}{(n-r)!r!}$

So, we have:

$Total = ^{U + G}C_r$

$Total = ^{3 + 5}C_4$

$Total = ^8C_4$

$Total = \frac{8!}{(8-4)!4!}$

$Total = \frac{8!}{4!4!}$

Using a calculator, we have:

$Total = 70$

The number of ways of selecting 2 from 3 undergraduates is:

$U = ^3C_2$

$U = \frac{3!}{(3-2)!2!}$

$U = \frac{3!}{1!2!}$

$U = 3$

The number of ways of selecting 2 from 5 graduates is:

$G = ^5C_2$

$G = \frac{5!}{(5-2)!2!}$

$G = \frac{5!}{3!2!}$

$G =10$

So, the probability is:

$Pr = \frac{G * U}{Total}$

$Pr = \frac{10*3}{70}$

$Pr = \frac{30}{70}$

$Pr = 0.4286$

5 0

2 years ago

ozzi

Hope this helps, I searched it up for you

6 0

1 year ago

15x+98=105 What is the value of x and please show your work. :)

Yuliya22 [10]

Answer:

15x+98=105

-98 -98

15x=7

/15 /15

x=7/15

Step-by-step explanation:

x=7/15

4 0

3 years ago

PLEASE HELP!!!!!!!!<br> What is the 8th term of this sequence? 1,-1/2,1/4,-1/8

Tom [10]

This is a geometric sequence with first term 1 and common ratio -1/2. r=-1/2.

a(n) = a(1)*(r)^(n-1).

Check: If n=2 our formula must return -1/2. Does it?

a(2) = 1(-1/2)^(2-1) = (-1/2)^1 = - 1/2. Yes.
a(3) should be 1/4. Is it? a(3) = (-1/2)^(3-1) = 1/4 Yes.

Then a(8) = (-1/2)^(8-1) = (-1/2)^7 = -1 / 2^7 = -1/128 (answer)

7 0

3 years ago