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STatiana [176]
3 years ago
7

3(x+1)-5=3x-2 Option1: no solution Option2:infinite solutions Option3:one solution

Mathematics
2 answers:
V125BC [204]3 years ago
7 0

Answer:

im pretty sure it no solution 0 = 0

hope this helps if does brainliest :)

Step-by-step explanation:

the solution equals 0

Vikentia [17]3 years ago
3 0

Answer:

Simplify 3(x+1)−5.

3x−2=3x−2

Move all terms containing x to the left side of the equation.

−2=−2 Since −2=−2 , the equation will always be true for any value of x

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

(−∞,∞)

Option2 : infinite solutions

Step-by-step explanation:

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What is the shape of the cross-section formed when a plane containing line AC and line EH intersects this cube? What is the area
velikii [3]

Answer:

Cross section is a rectangle.

Area of cross section = 16 sqrt(2) = 22.63 sq. units (to 2 decimals)

Step-by-step explanation:

Given a cube.

top face ABCD is parallel and congruent to bottom face EFGH  ........(1)

justified by the properties of cubes

Sides AE and CH are perpendicular to faces ABCD and EFGH ..........(2)

justified by the properties of cubes

Diagonals AC and EH are congruent ......................(3)

justified by (1), congruent top and bottom faces  

Consider cross-section ACHE

AC is congruent and parallel to  EH   (1) & (3)

EA & HC are perpendicular to AC      (2)

Therefore the quadrilateral ACHE is a rectangle.

Length of diagonal AC = sqrt(4^2+4^2) = 4 sqrt(2)  ..........pythagoras theorem

AE = CH = DG = 4      properties of cube, all sides equal

Area of ACHE = 4* 4sqrt(2) = 16 sqrt(2) = 22.63 sq. units

4 0
3 years ago
latrell will rotate △abc 180° about one of the labeled points. latrell says, “the image will only touch the pre-image at exactly
777dan777 [17]
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3 years ago
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If Upper X overbar equals 62​, Upper S equals 8​, and n equals 36​, and assuming that the population is normally​ distributed, c
marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=62 represent the sample mean

\mu population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size  

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=36-1=35

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that t_{\alpha/2}=2.72

Now we have everything in order to replace into formula (1):

62-2.72\frac{8}{\sqrt{36}}=58.373    

62+2.72\frac{8}{\sqrt{36}}=65.627    

So on this case the 99% confidence interval would be given by (58.373;65.627)    

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0
3 years ago
Name a pair of complementary angles.
allochka39001 [22]

complementary angles = 90 degrees

two angles would be BGC (35 degrees) and CGD ( 55 degrees)

35+55 = 90

8 0
2 years ago
(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3 to the power of negative 2 over 2 to the power of 3, whole to the power of 4 ⋅ 2^28 (5 points)
Otrada [13]

Answer:

Step-by-step explanation:

(2^8 ⋅ 3^−5 ⋅ 6^0)^−2 ⋅ 3

(2^8 ⋅ 3^−5 ⋅ 6^0)^−6

(a^m)^n=a^m*n

So,

(2^8*-6) * (3^−5*-6) * (6^0*-6)

(2^-48) (3^30) (6^0)

a^0=1

So,

(2^-48) (3^30) (1)

<u>(2^-48) (3^30)</u>

I hope this helps you friend!

3 0
3 years ago
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