None of your options, not via complete the square nor quadratic the formula.
Solve for x over the real numbers:
x^2 + 8 x + 9 = 0
x = (-8 ± sqrt(8^2 - 4×9))/2 = (-8 ± sqrt(64 - 36))/2 = (-8 ± sqrt(28))/2:
x = (-8 + sqrt(28))/2 or x = (-8 - sqrt(28))/2
sqrt(28) = sqrt(4×7) = sqrt(2^2×7) = 2sqrt(7):
x = (2 sqrt(7) - 8)/2 or x = (-2 sqrt(7) - 8)/2
Factor 2 from -8 + 2 sqrt(7) giving 2 (sqrt(7) - 4):
x = 1/22 (sqrt(7) - 4) or x = (-2 sqrt(7) - 8)/2
(2 (sqrt(7) - 4))/2 = sqrt(7) - 4:
x = sqrt(7) - 4 or x = (-2 sqrt(7) - 8)/2
Factor 2 from -8 - 2 sqrt(7) giving 2 (-sqrt(7) - 4):
x = sqrt(7) - 4 or x = 1/22 (-sqrt(7) - 4)
(2 (-sqrt(7) - 4))/2 = -sqrt(7) - 4:
Answer: x = sqrt(7) - 4 or x = -sqrt(7) - 4_____________________________________________________
Solve for x:
x^2 + 8 x + 9 = 0
Subtract 9 from both sides:
x^2 + 8 x = -9
Add 16 to both sides:
x^2 + 8 x + 16 = 7
Write the left hand side as a square:
(x + 4)^2 = 7
Take the square root of both sides:
x + 4 = sqrt(7) or x + 4 = -sqrt(7)
Subtract 4 from both sides:
x = sqrt(7) - 4 or x + 4 = -sqrt(7)
Subtract 4 from both sides:
Answer: x = sqrt(7) - 4 or x = -4 - sqrt(7)
Answer:
maybe do the math
Step-by-step explanation:
See attachment for the drawing of the perpendicular at a point c on line ab such the ac = 3.5 cm
<h3>How to draw the perpendicular at a point c on line ab such the ac = 3.5 cm?</h3>
The given parameters are:
Length of segment AB = 7 cm
Also, we have:
Point C is located on line segment AB
This means that:
Length of segment AC = Length of segment BC = 3.5 cm
When represented on a line segment, we have:
A C B
See attachment for the drawing of the perpendicular at a point c on line ab such the ac = 3.5 cm
Read more about perpendicular line at:
brainly.com/question/1865107
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Answer: $6000
Step-by-step explanation:
Multiply the cost of the book by the decimal equivalent of 12% (25 x .12). this equal 3 dollars per book. 2,000 copies of the book were sold, so you would multiply 2000 by 3. 2000 x 3 = 6000
