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ad-work [718]
2 years ago
7

Find the numerical coefficient of 7x^3​

Mathematics
1 answer:
Travka [436]2 years ago
4 0

Answer:

7

Step-by-step explanation:

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PC-CSIL
pav-90 [236]

The equality used is Subtraction property of equality

Option A is correct

Step-by-step explanation:

We need to identify which option best explains or justifies Step 1.

Step 1 is: -c = ax^2 + bx

The given equation is: 0 = ax^2 + bx + c

To get the equation for step 1 we need to subtract c on both sides of equation i.e using subtraction property of equality

0-c = ax^2 + bx + c-c

-c = ax^2 + bx

So, The equality used is Subtraction property of equality

Option A is correct.

Keywords: Solving Quadratic Equations

Learn more about Solving Quadratic Equations at:

  • brainly.com/question/4460262
  • brainly.com/question/7361044
  • brainly.com/question/1414350

#learnwithBrainly

5 0
3 years ago
Alguem pra me ajudar na minha prova de matematica daqui 10 min? 8 ano
o-na [289]
Noenoenoenoenoenoenoenoenoe
3 0
2 years ago
Removing which point from the coordinate plane would make the graph a function of x? mc006-1.jpg
Marianna [84]
B. (-2,1)

By checking the x coordinates, I saw there was two -2, but the output was different, so one of them had to be taken out to make it a function.

Function: Every input must have one out must.
5 0
3 years ago
What would be the answer please explain
sp2606 [1]

Using the line of the best fit, the predicted student's score in English test is 48

<h3>How to determine the student's score in English?</h3>

From the question, we have:

Mathematics score = 60

The scores in English tests are plotted on the y-axis.

On the given graph, we have:

(x,y) = (60,48)

This means that when x = 60, the value of y is 48

This in other words means that the student's score in English test is 48

Read more about line of best fit at:

brainly.com/question/17261411

#SPJ1

6 0
2 years ago
Evaluate 66 - 20 - 32 1/4
BigorU [14]

Answer:

13.75

Step-by-step explanation:

66-20- 32 1/4

66-20- 32.25

46-32.25

13.75

8 0
3 years ago
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