Answer:
If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 is 0.01.
Step-by-step explanation:
p-value is the probability of observing a result which is at least as extreme as we calculated in our actual workings, assuming the Null hypothesis to be true.
The calculate p-value is 0.01. In the question statement we are given that the alternate hypothesis is:
"Population Proportions are not equal"
Since, Null and Alternate Hypothesis are negations of each other, the Null Hypothesis would be:
"Population Proportions are equal"
We assume the null hypothesis to be true, perform the tests on the sample and obtain a result.
The results we obtained is:
The sample difference is 0.62
Fitting all this data, in the definition of p value tell us that:
The probability of obtaining a sample difference of atleast 0.62 is 0.01, if the population proportions are same.
This matches with the option B. Therefore, the correct answer is:
If the proportions of all cats with spotted markings is the same for both populations, the probability of observing a sample difference of at least 0.62 is 0.01.
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