Find the values of x and y.

Mathematics

2 answers:

vitfil [10]3 years ago

6 0

Answer:

Step-by-step explanation:

Your question is incomplete

Over [174]3 years ago

4 0

Answer:

How to find X and Y value?

If you have given an equation, you see the x and y in it. Just taking second equation and think any common factor between x's variable. With common factor, multiply both and you will find the value of y and put it in any equation, you will find the value of X.

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What is the quotient (3x^2+8x-3)/ (x+3)

Dvinal [7]

Answer:

The quotient ix 3x - 1.

Explanation:

Use Long division:

3x - 1 <------------quotient.

---------------------

x + 3) 3x^2 + 8x + 3

3x^2 + 9x

-------------

-x + 3

-x - 3

------

6 <---------remainder.

6 0

3 years ago

Rhea sold 6 boxes of blueberry muffins and 8 boxes of corn muffins at the bake sale. Each box contained 18 muffins. The muffins

Elenna [48]

6 boxes of blueberry muffins and 8 boxes of corn muffins

Since we know that each box has 18 muffins, we can multiply both 6 and 8 to determine the amount of muffins present

6 • 18 = 108 blueberry muffins
8 • 18 = 144 corn muffins

To determine the price, you multiply each type of muffin by 0.50 as each muffin is worth $0.50

108 • 0.50 = 54
144 • 0.50 = 72

You add these two together to get the price

54 + 72 = $126

If you explain what the estimate is, if I didn’t answer that along the way, I can help answer it for you.

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bx%7D%20%20-%20%20%20%7B3%7D%5E%7Bx%7D%20%20%3D%20%20%20%20%5Csqrt%7B%20%7B6%7D

strojnjashka [21]

Answer:

x = 0

Step-by-step explanation:

${2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {9}^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {( {3}^{2}) }^{x } } \\ \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {({3)}^{2x}}}\\ \\ {2}^{x} - \cancel{{3}^{x}} = \sqrt{ {6}^{x} } - \cancel{ {3}^{x} } \\ \\ {2}^{x} = \sqrt{ {6}^{x} } \\ squaring \: both \: sides \\ \\ {( {2}^{x} )}^{2} = {(\sqrt{ {6}^{x} })}^{2} \\ \\ {2}^{2x} = {6}^{x} \\ \\ {2}^{2x} = {(2 \times 3)}^{x} \\ \\ {2}^{2x} = {2 ^{x} \times 3}^{x} \\ \\ \frac{ {2}^{2x} }{ {2}^{x} } = 3^{x} \\ \\ {2}^{2x - x} = {3}^{x} \\ \\ {2}^{x} = {3}^{x} \\ \\ \frac{ {2}^{x} }{ {3}^{x} } = 1 \\ \\ \bigg( \frac{2}{3} \bigg)^{x} = 1 \\ \\ \implies \: x = 0 \\ \\ \because \: for \: x = 0 \\ \\ \bigg( \frac{2}{3} \bigg)^{0} = 1$