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Nookie1986 [14]
3 years ago
14

A)Three out of my four brothers play soccer. What percent of my brothers do not play soccer?

Mathematics
2 answers:
exis [7]3 years ago
7 0
A. 1)25%
B. 2)7
C. 3)48
skad [1K]3 years ago
3 0
A) 1)25%
b) 2)7
c) 3)48
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You have 350 feet of fencing to enclose a rectangular plot that borders on a river. If you do not fence the side along the river
IrinaVladis [17]

The length and width that will maximize the area are 175 ft and 87.5 ft respectively

The largest area that can be enclosed is 15312.5 ft²

<h3>Area of a rectangle</h3>
  • area = lw

where

l = length

w = width

The fencing is 350 ft it is use to enclose a rectangular plot with a river occupying one part.

Therefore,

perimeter = l + 2w

350 = l + 2w

l = 350 - 2w

area = (350 - 2w)w

(350 - 2w)w = 0

where

w = 0 or 175

average = 175/2 = 87.5

Hence, the max area is at w = 87.5 ft

Therefore,

l = 350 - 2(87.5) = 175 ft

length = 175 ft

width =  87.5 ft

Therefore,

area = 175 × 87.5 = 15312.5 ft²

Therefore, the largest area that can be enclosed is 15312.5 ft²

learn more on rectangle here: brainly.com/question/11630499

4 0
2 years ago
Evaluate each function: 1. p(a) = 3a-2; find p(-5) 2. h(t) = 4t+2; find h(-4) 3. f(a) = 3a-4; find f(1) 4. g(x) = 3x+ 1; find g(
frutty [35]
A-2x = 45 explained the theropod waysiver
3 0
2 years ago
Plssssss help fast!!!!Launching From a Tower
aleksandrvk [35]

Answer:

A. h = 64

B.  t = 4 -> 4 seconds

C. t = 1.5 -> 1.5 seconds

D. maximum height is 100 ft

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

Step-by-step explanation:

h = -16t2 + vt + 64

A. What tower platform height was the projectile launched from?

when the projectile was not launched, t = 0

h = -16(0)^2 + v(0) + 64 = 64

B. How long was the projectile in the air?

if the projectile lands, its height = 0 so substitute 0 for h

0 = -16(t)^2 + 48(t) + 64

  = -16(t^2 - 3t -  4)

 = -16(t - 4)(t + 1)

t = 4 or t = -1

Since time can not be negative, t = -1 can not be the answer. Therefore, the projectile lands when t = 4 or 4 seconds.

C. When did it reach its maximum height?

maximum -> t=-b/2a where in -16(t)^2 + 48(t) + 64, b = 48 and a = -16

t = -48/-32 = 1.5

D. What was its maximum height?

plug t = 1.5 into -16(t)^2 + 48(t) + 64

-16(1.5)^2 + 48(1.5) + 64 = -36 + 72 + 64 = 100

E. The domain that makes sense for the function in this context is t

is any positive real number since time can not be negative.

6 0
2 years ago
What is BC of the prism
REY [17]
It is the lateral edge as it is an edge and it is on the lateral area.
4 0
3 years ago
Find the x and y intercepts<br> c) x + 3y - 12=0
mojhsa [17]
To get x intercept:
let y=0,x➖12=0,x=12
so x intercept point (12,0)
To get y intercept:
let x=0,3y➖12=0,y=4
so y intercept point (0,4)
7 0
2 years ago
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