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Nadya [2.5K]
3 years ago
14

In ANOP, the measure of Angle P=90°, PN = 89 feet, and OP = 74 feet. Find the measure

Mathematics
2 answers:
padilas [110]3 years ago
8 0

Answer:

O = 50.3 degrees

Step-by-step explanation:

tan O = 89/74

tan O = 1.2027

O = 50.3 degrees

timofeeve [1]3 years ago
8 0

Answer:50.3

Step-by-step explanation:

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A video company randomly selected 100 of its subscribers and asked them how many hours of shows they watch per week. Of those su
Alik [6]

Answer:

1,135 people

For every 100 people only 45 people watch more than 10 hours per week. So, the ratio is (45/100), since the company has 2500 we want to know what (x/2500) is. The total ratio becomes (1,135/2,500).

The number is found by dividing 2500 by 100 to receive the common factor of 25. You multiply 45 by 25 to receive your total answer.

Step-by-step explanation:

For every 100 people only 45 people watch more than 10 hours per week. So, the ratio is (45/100), since the company has 2500 we want to know what (x/2500) is. The total ratio becomes (1,135/2,500).

The number is found by dividing 2500 by 100 to receive the common factor of 25. You multiply 45 by 25 to receive your total answer.

8 0
3 years ago
A vending machine has 5 colors (white, red, green, blue, and yellow) of gumballs and an equal chance of dispensing each. A secon
babunello [35]

Answer:

1/20

Step-by-step explanation:

6 0
3 years ago
Solve.
Tema [17]
From 1st equation
d + e = 2
d = 2 - e

From 2nd equation, subtitute d with 2 - e
d - e = 4
2 - e - e = 4
2 - 2e = 4
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e = -1

Find d
d = 2 - e
d = 2 - (-1)
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4 0
3 years ago
Help with #19 plzzz!!!???
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Do "42 + 12" Since 7 x 6 is 42 and 4 x 3 is 12.
5 0
4 years ago
Determine whether the integral is convergent or divergent. [infinity] 7 e−1/x x2 dx convergent divergent Changed: Your submitted
inessss [21]

I suppose the integral could be

\displaystyle\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx

In that case, since -\frac1x\to0 as x\to\infty, we know e^{-1/x}\to1. We also have \left(e^{-1/x}\right)'=\frac{e^{-1/x}}{x^2}>0, so the integral is approach +1 from below. This tells us that, by comparison,

\displaystyle\frac{e^{-1/x}}{x^2}\le\frac1{x^2}\implies\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx\le\int_7^\infty\frac{\mathrm dx}{x^2}

and the latter integral is convergent, so this integral must converge.

To find its value, let u=-\frac1x, so that \mathrm du=\frac{\mathrm dx}{x^2}. Then the integral is equal to

\displaystyle\int_{-1/7}^0e^u\,\mathrm du=e^0-e^{-1/7}=1-\frac1{\sqrt[7]{e}}

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3 years ago
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