Square-root of two multiplied by the cube-root of 2
=sqrt(2)*(2)^(1/3)
=2^(1/2)*2^(1/3)
=2^(1/2+1/3) multiplication rule of exponents
=2^((3+2)/6)
=2^(5/6)
=(2^5)^(1/6).........sixth root of 2^5
=(32)^(1/6) ............sixth root of 32.
For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
So the question ask to find the displacement vector and the distance from the submarine to the boat. Base on my calculation the displacement value of the given data you give is <(5-3),(1-4)(-5-0)>. I hope you are satisfied with my answer and feel free to ask for more
Answer: y=6
Step-by-step explanation:
The given number is y.
According to the question,
Step 1 . subtracts three from the number (y-3), then doubles it
i.e. Final number = 2(y-3)
Step 2 . subtracts three again i.e. (2(y-3)-3), and doubles the number again
i.e. Final result = 2(2(y-3)-3)
If the result is his original number y, then
2(2(y-3)-3) =y
⇒ 2(2y-6-3)=y [ using distributive property]
⇒ 2(2y-9)=y
⇒ 2(2y)-2(9)=y [ using distributive property]
⇒ 4y -18=y
⇒ 4y -y= 18
⇒ 3y= 18
⇒ y= 6 [Divide both sides by 3]
Hence, y=6
Wym their was no growth rate it lost 53,500 in those 15 years at a rate of about 3,566 a year
