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3 years ago

What value of x makes this equation true? HELP ASAP I GOTTA TURN THIS HOMEWORK I N PLZ PLZ HELP

Mathematics

2 answers:

ANTONII [103]3 years ago

8 0

Answer: x =-1

Step-by-step explanation:

4x-18=7x-15

4x-7x=-15+18

-3x=3 , x=-1 since 3/-3=x

IrinaVladis [17]3 years ago

6 0

Your answer would be -1

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Step-by-step explanation:

Note that the triangle has 2 congruent base angles, both 45°

This means the triangle is isosceles with congruent legs, then

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The 2 equations are
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3 years ago

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vekshin1

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4 years ago

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5/10+13/100 <br> what is the value of the expression

cluponka [151]

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Step-by-step explanation:

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3 years ago

. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte

Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160$

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240$

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

$\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}$

4 0

2 years ago