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laila [671]
3 years ago
6

Two vertices of a square are (12, 0) and (12, 12). What is the smallest possible area the square can have?

Mathematics
2 answers:
zavuch27 [327]3 years ago
7 0
It is 72 because it is the smallest possible area the square can  have
Burka [1]3 years ago
4 0
The answer is 72 because the vertices are on the lower left corner and the upper right corner. which means that 12 units is the length of the hypotenuse.
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If y varies directly with x, with k=0.75,what is the value of y when x=12
erma4kov [3.2K]

Answer:

9

Step-by-step explanation:

y=x

y=kx

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y=0.75×12

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Step-by-step explanation:

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A company is planning to manufacture snowboards. The fixed costs are $ 100$100 per day and total costs are ​$55005500 per day at
Rama09 [41]

Answer:

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C(x)=100+270x

Step-by-step explanation:

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4 0
3 years ago
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7 0
2 years ago
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Find the value of the expression x3−y3+x2+y2+3 by substituting x=−2 and y=1.
vaieri [72.5K]

\\ \sf\dashrightarrow x^3-y^3+x^2+y^2+3

\\ \sf\dashrightarrow (-2)^3-(1)^3+(-2)^2+(1)^2+3

\\ \sf\dashrightarrow -8-1+4+1+3

\\ \sf\dashrightarrow -9+8

\\ \sf\dashrightarrow -1

8 0
3 years ago
Read 2 more answers
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