Let the number be x,
(1/2)x=1+(1/3)x
Solving for x,
(1/2)x-(1/3)x=1+(1/3)x-(1/3)x
(1/2)x-(1/3)x=1
(1*3/6)x-(1*2/6)x=1
(3/6)x-(2/6)x=1
(1/6)x=1
6*(1/6)x=6*1
Therefore, x=6

7 0

3 years ago

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Anyone have the answer?

ruslelena [56]

Answer:

yes

Step-by-step explanation:

6 0

2 years ago

What is the product of 8 times 5 times 18

Solnce55 [7]

8 x 5 = 40
40 x 18 = 720
Hope this helps!

5 0

3 years ago

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Verify that [tan(theta) + cot(theta)]^2 = sec^2(theta) + csc^2(theta)

Wittaler [7]

(tanθ + cotθ)² = sec²θ + csc²θ

Expand left side: tan²θ + 2tanθcotθ + cot²θ

Evaluate middle term: 2tanθcotθ = $2*\frac{sin\theta}{cos\theta}*\frac{cos\theta}{sin\theta}$ = 2

⇒ tan²θ + 2+ cot²θ

= tan²θ + 1 + 1 + cot²θ

Apply trig identity: tan²θ + 1 = sec²θ

⇒ sec²θ + 1 + cot²θ

Apply trig identity: 1 + cot²θ = csc²θ

⇒ sec²θ + csc²θ

Left side equals Right side so equation is verified

7 0

3 years ago