Same as handshake problem.
Each of n persons plays against n-1 persons for a total of n(n-1)/2 games.
The division by 2 is necessary to avoid double counting the game A vs B and B vs A.
For n=8, then number of games played in the first round is 8(8-1)/2=28 games.
Answer:
rationalizing
Step-by-step explanation:
Answer:
r
<
−
6
Step-by-step explanation:
