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zheka24 [161]
3 years ago
12

The price-demand and cost functions for the production of microwaves are given as

Mathematics
1 answer:
Nikolay [14]3 years ago
7 0

Answer:

<u>ALTERNATIVE 1</u>

a. Find the profit function in terms of x.

P(x) = R(x) - C(x)

P(x) = (-60x² + 275x) - (50000 + 30x)

P(x) = -60x² + 245x - 50000

b. Find the marginal cost as a function of x.

C(x) = 50000 + 30x

C'(x) = 0 + 30 = 30

c. Find the revenue function in terms of x.

R(x) = x · p

R(x) = x · (275 - 60x)

R(x) = -60x² + 275x

d. Find the marginal revenue function in terms of x.

R'(x) = (-60 · 2x) + 275

R'(x) = -120x + 275

The answers do not make a lot of sense, specially the profit and marginal revenue functions. I believe that the question was not copied correctly and the price function should be p = 275 - x/60

<u>ALTERNATIVE 2</u>

a. Find the profit function in terms of x.

P(x) = R(x) - C(x)

P(x) = (-x²/60 + 275x) - (50000 + 30x)

P(x) = -x²/60 + 245x - 50000

b. Find the marginal cost as a function of x.

C(x) = 50000 + 30x

C'(x) = 0 + 30 = 30

c. Find the revenue function in terms of x.

R(x) = x · p

R(x) = x · (275 - x/60)

R(x) = -x²/60 + 275x

d. Find the marginal revenue function in terms of x.

R(x) = -x²/60 + 275x

R'(x) = -x/30 + 275

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when a spherical balloon filled with air diameter of 6 inches what's the volume of balloon in cubic inches
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Read 2 more answers
Answer number 1 please and thankyou.​
Ksivusya [100]
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7 0
2 years ago
Write an expression for the number of small squares in pattern n<br><br> Please properly answer.
antoniya [11.8K]

Answer:

(n + 2)² + 6

Step-by-step explanation:

pattern 1:

Total squares = 15

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Pattern 2:

Total squares = 22

4² + 6

Pattern 3:

Total squares = 31

5² + 6

Looking at the series,

There is an Increment of 1 in squared integer as the pattern increases; there is also a constant integer of 6

Hence, expressing the nth pattern in the form ;

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3 0
3 years ago
NEED ANSWER ASPA.... PLS HURRY
a_sh-v [17]
We have that
y=- x^{2} +36

we know that
Is the equation of a vertical parabola open down
so
the vertex is a maximum

step 1
convert the equation of the parabola in the vertex form
y=- x^{2} +36 \\ y-36=- x^{2}

the vertex (h,k) is the point (0,36)

Part a) The point on the graph where the height of the tunnel is a maximum is (0,36)

Part b) The points on the graph where the height of the tunnel is zero feet is when y=0
so
for y=0
- x^{2} +36=0 \\ x^{2} =36 \\ x= (+/-) 6

the points are (-6,0)  and (6,0)

see the attached figure 

5 0
3 years ago
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