The molecule is as follows;
H₃C---C==CH₂
|
H
--- represents single bonds whilst == represents double bonds
Single bonds are formed by sigma orbital head on overlap between sigma orbitals of C and H in the case of C-H bonds and between C sigma orbitals in the case of C-C bonds
the number of sigma bonds are therefore the number of single bonds which are:
6 C-H bonds
2 C-C bonds
altogether 8 sigma bonds
p orbitals side- on overlap forms a pi bond. In double bonds, there's one sigma bond and one pi bond.
number of double bonds - 1 C=C therefore one pi bond
Answer is <span>4) 8 sigma and 1 pi</span>
Y-intercept form is y=-3x+19, I’m not sure what you question is
Take your x values in each coordinate and subtract 2, and take your y values and subtract 1.
Q (0-2), (-1-1)
= (-2,-2)
D (-2-2), (2-1)
= (-4, 1)
V (2-2), (4-1)
= (0,3)
J (3-2), (0-1)
= (1,-1)
You can also draw it on a graph and then translate all coordinates 2 units left and 1 down to see the end results.
The sample % of these two populations would be 100/size (of student body at each school) x 100 so this would compare the two student bodies preferences for the particular type of candy bar. However, the actual % of the whole student body at each school would be a factor also. If the high school only had 200 students then this would be 50% representative but if the middle school had say 500 students this would only be 20% representative so this would have to be taken into account too. It might be more representative to have the same % of the student bodies respectively for the sample.
-8.70833333333 about but you can round to the nearest tenth (-8.7) or nearest whole number (-9)
