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3 years ago

Of the 28 muffins left in the fridge, 16 of them have blueberries. What

Mathematics

1 answer:

Igoryamba3 years ago

5 0

Answer:

43% or 3/7

Explanation: Subtract 16 from 28 to get the number of muffins with no blueberries. Then you get 12/28 which is simplified to 3/7 or 43 percent.

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An object is launched with a velocity at 64 feet per second from a platform 30 feet high. the function H(t)= -16t2+64t+30 repres

PolarNik [594]

To find the maximum or minimum value of a function, we can find the derivative of the function, set it equal to 0, and solve for the critical points.

H'(t) = -32t + 64

Now find the critical numbers:

-32t + 64 = 0

-32t = -64

t = 2 seconds

Since H(t) has a negative leading coefficient, we know that it opens downward. This means that the critical point is a maximum value rather than a minimum. If we weren't sure, we could check by plugging in a value for t slightly less and slighter greater than t=2 into H'(t):

H'(1) = 32

H'(3) = -32

As you can see, the rate of change of the object's height goes from increasing to decreasing, meaning the critical point at t=2 is a maximum.

To find the height, plug t=2 into H(t):

H(2) = -16(2)^2 +64(2) + 30 = 94

The answer is 94 ft at 2 sec.

4 0

3 years ago

ANSWER PLS! DUE TODAY!!!

makvit [3.9K]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 1

Helga [31]

Let x and y be the upper and lower class limit of frequency distribution.

Given, width of the class = 5

⇒ x-y= 5 …

Also, given lower class (y) = 10 On putting y = 10, we get

x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15

Hence, the upper class limit of the highest class

=(Number of continuous classes x Class width + Lower class limit of the lowest class)

= 5 x 5+10 = 25+10=35

Hence,’the upper class limit of the highest class is 35.

<em><u>Alternate Method</u></em><em><u>.</u></em>

After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.

Thus, the highest class is 30-35..

<h3>Hence, the upper limit of this class is 35.</h3>

4 0

2 years ago

Use substitution to solve the system.<br><br> X= ?<br> Y= ?<br><br> 5x+4y = -10<br> x = 3y+17

nikklg [1K]

Answer:

x=3.4

y=-6.75

Step-by-step explanation:

5x+4y=-10 (equation 1 )

-5x+3y=-17 (equation 2)

7y=-27

y=-6.75

substitution (equation 1 ) y=-6.75

5x-27=-10

5x=17

x=3.4

4 0

3 years ago

A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, & 30 years.

Alika [10]

Complete Question

A hypothetical population consists of eight individuals ages 13 14 17 20 21 22 24 30 years.

A: what is the probability that a person in this population is a teenager?

B: what is the probability of selecting a participant who is at least 20 years old?

We have that probability that a person in this population is a teenager and probability of selecting a participant who is at least 20 years old is

From the question we are told

A hypothetical population consists of eight individuals ages 13, 14, 17, 20, 21, 22, 24, & 30 years.

P(T)=0.38
P(T')=0.63

Generally the equation for the probability that a person in this population is a teenager is mathematically given as

$P(T)=\frac{no of teens}{n}\\\\P(T)=\frac{3}{8}$

P(T)=0.38

Generally the equation for the probability of selecting a participant who is at least 20 years old is mathematically given as

$P(T)=\frac{ participants\ who\ is\ at\ least\ 20\ years old}{n}\\\\P(T)=\frac{5}{8}$

P(T')=0.63

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6 0

2 years ago