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vodka [1.7K]
3 years ago
12

PLS HELP gIVING BRAINLIEST

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
8 0
The answer is b

Because is get the same answer
Mandarinka [93]3 years ago
4 0

Answer: i think it's b

Step-by-step explanation:

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Ray Of Light [21]
It is B, A, E, F. Hope that’s all of them <3
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What is the monthly payment on a 15-year loan of $72,700 if the annual interest rate is 12%?
Trava [24]

Answer:

sorry this is for points

Step-by-step explanation:

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5 0
3 years ago
Find the equation of the line through point (5,1) and perpendicular to 5x−y=−3. Use a forward slash (i.e. "/") for fractions (e.
IRINA_888 [86]
Y = -1/5x + 2

A line perpendicular to another line has an opposite reciprocal slope. What opposite means is that you flip the sign (from - to + or from + to -) and reciprocal means that you flip the numerator and denominator (so if line A is perpendicular to line B and line As slope is -3, line Bs slope would be 1/3).

First find the slope of 5x - y = -3
Add y to both sides
5x = y - 3
Add 3 to both sides
y = 5x + 3

So the slope of the line is 5. That means the slope of of the perpendicular line is -1/5.

Plug the slope of the perpendicular line and the point (5, 1) into point slope form to solve the equation

y - y1 = m(x - x1)
y - 1 = -1/5(x - 5)
y - 1 = -1/5x + 1
y = -1/5x + 2
3 0
2 years ago
A circular disc has a circumference of 16pi meters. if we multiply the radius of the circular disc is by 10, what is the circumf
Flauer [41]

The circumference of the new disc 160Π that is 10 time of old circumference.

Step-by-step explanation:

Given,

Circumference of circular disc = 16Π (pi = Π)

Let, the radius of the circle be 'r'

Formula

The circumference of a circle with r radius = 2 Π r

According to the problem,

2 Π r = 16Π

or, 2r = 16 ( by eliminating the value of Π from both the side)

or, r = 8

Now, we multiply the radius by 10

so, the new radius is 8 X 10 = 80

Now the circumference = 2 Π X 80

= 160Π

Hence, the new circumference also will be 10 times of the older one.

6 0
4 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
AURORKA [14]

Answer:

(−0.103371 ; 0.063371) ;

No ;

( -0.0463642, 0.0063642)

Step-by-step explanation:

Shift 1:

Sample size, n1 = 30

Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm

Shift 2:

Sample size, n2 = 25

Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17

Mean difference ; μ1 - μ2

Zcritical at 95% confidence interval = 1.96

Using the relation :

(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)

(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)

Lower boundary :

-0.02 - 0.0833710 = −0.103371

Upper boundary :

-0.02 + 0.0833710 = 0.063371

(−0.103371 ; 0.063371)

B.)

We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.

C.)

For sample size :

n1 = 300 ; n2 = 250

(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)

Lower boundary :

-0.02 - 0.0263642 = −0.0463642

Upper boundary :

-0.02 + 0.0263642 = 0.0063642

( -0.0463642, 0.0063642)

7 0
3 years ago
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