Let any integer be represented by x.
Then, the consecutive integer (the number that follows) should be x+1.
The statement wants us to prove;
(x+1)²-x²=x+(x+1) <-- solve left hand side
x²+x+x+1²-x²
2x+1 (solution for left hand side)
Now solve for right hand side.
x+(x+1)= 2x+1
As noticed, the LHS=RHS (left hand side= right hand side), therefore, the difference of squared consecutive numbers subtracted is equal to the sum of the two integers.
Hope I helped :)
Answer: True for all <em>b</em>.
Step-by-step explanation: To tangent a equation, find if the variable is true.
1. Add 56 to both sides.
63b - 56 + 56 = 63b - 56 + 56 = 7
2. Simplify.
63b = 63b
3. Simplify again for your answer.
0 = 0
Hence, both sides are equal.
Let me know if you have any questions.
~ Lily, from Brainly.
Answer:
5/64
Step-by-step explanation:
20/256
10/128
5/64
Answer:
8,039
Step-by-step explanation:
4097
3188
754
---------
8039
Hope you don’t mind reading handwriting. I named two of the angles to make the explanation easier
