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3 years ago

Can someone help me with question 1-5

Mathematics

2 answers:

seraphim [82]3 years ago

7 0

The answer would be B

tigry1 [53]3 years ago

6 0

The slope m =(5-1)/(4--1) = 4/5
The point slope equation is:
y - y1 = m(x-x1)
y-1 = (4/5)(x+1)
y = .8x + 1.8
Distance is SQRT(4^2 + 5^2) = SQRT (41)

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3 years ago

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dsp73

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4 years ago

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Nat2105 [25]

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Step-by-step explanation:

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3 years ago

Number 2 I need help on how to solve it

Hunter-Best [27]

Let's simplify the following expression:

$\text{ }\frac{\text{ \lparen2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{\text{ 6x}^5\text{y}^{-4}\text{z}^{-5}}{\text{ \lparen2x}^6\text{y}^3\text{z}^{-3})^2}$

We get,

$\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{ }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}$ $\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}$ $\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}$

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1 year ago

The ratio of the width to the length of a painting is 3 to 7. If the painting is 42 in. long how wide is it

belka [17]

If length is 42 inches, then width is 18 inches.

Step-by-step explanation:

We are given ratio of width to the length of a painting i.e 3 to 7. If the painting is 42 inches long, then how wide it is?

Solving:

$\frac{width}{length}=\frac{width}{length}\\ \frac{3}{7}=\frac{w}{42}\\ Cross\,\,multiply:\\3*42=w*7\\126=w*7\\w=\frac{126}{7}\\w=18$

So, If length is 42 inches, then width is 18 inches.

Keywords: Ratio

Learn more about Ratio at:

#learnwithBrainly

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3 years ago