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ehidna [41]
2 years ago
9

Tangent this equation:

)" alt="63(b-1)+7=7(9b-8)" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
timurjin [86]2 years ago
7 0

Answer: True for all <em>b</em>.

Step-by-step explanation: To tangent a equation, find if the variable is true.

1. Add 56 to both sides.

63b - 56 + 56 = 63b - 56 + 56 = 7

2. Simplify.

63b = 63b

3. Simplify again for your answer.

0 = 0

Hence, both sides are equal.

Let me know if you have any questions.

~ Lily, from Brainly.

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IT TUVW is reflected across the line y = .x, what are the coordinates of V'?
Kay [80]

Answer:

Its A

Step-by-step explanation:

3 0
2 years ago
Which of the pairs of events below is mutually exclusive?
Nady [450]

Answer:

Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards.

Step-by-step explanation:

Given four pair of events:

1. Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards

2. Drawing a 2 and drawing a 4 with replacement from a standard deck of cards

3. Drawing a heart and then drawing a spade without replacement from a standard deck of cards

4. Drawing a jack and then drawing a 7 without replacement from a standard deck of cards

To find:

Which of the pairs is mutually exclusive?

Solution:

First of all, let us have a look at the definition of mutually exclusive events.

Mutually exclusive events do not have any case in common.

In other words, two events are known as mutually exclusive when both the events can not occur at the same time.

Now, let us have a look at the given options one by one:

1. Drawing an ace of spades and then drawing another ace of spades without replacement from a standard deck of cards.

We know that there is only one ace of spades in a standard deck.

Therefore, the two events can not occur one after the other, so these are mutually exclusive events.

2. Drawing a 2 and drawing a 4 with replacement from a standard deck of cards.

The two events can occur one after the other, so these are not mutually exclusive.

3. Drawing a heart and then drawing a spade without replacement from a standard deck of cards.

Separate cards are drawn one after the other, so not mutually exclusive.

4. Drawing a jack and then drawing a 7 without replacement from a standard deck of cards.

Separate cards are drawn one after the other, so not mutually exclusive.

3 0
2 years ago
The difference of the product of a number, y, and 3 and 24 is 237. Write an equation
lbvjy [14]

y + 3 +24 = 237

y + 27 = 237

y + 27 - 27 = 237 -27

y = 210

5 0
3 years ago
I really need help with this. You can answer this at any time if you want.​
Tcecarenko [31]

Answer:

1. a 3d rectangle

2. 40 in cubed

3. repeat

4. another repeat

Step-by-step explanation:

8 0
2 years ago
An investigator thinks that people under the age of forty have vocabularies that are different than those of people over sixty y
Kay [80]

Answer:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

Step-by-step explanation:

Information given

\bar X_{1}=14 represent the mean for sample 1 (younger)

\bar X_{2}=20 represent the mean for sample 2 (older)  

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=31 sample size for the group 2  

n_{2}=31 sample size for the group 2  

t would represent the statistic

System of hypothesis

We want to test if  that people under the age of forty have vocabularies that are different than those of people over sixty years of age, the system of hypothesis are:

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

The statistic is given by:

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=31+31-2=60  

Replacing the info given we got:

t=\frac{(14-20)-0}{\sqrt{\frac{5^2}{31}+\frac{6^2}{31}}}}=-4.28  

Now we can calculate the p value with the following probability:

p_v =2*P(t_{60}  

The p value is a very low value so then we have enough evidence to reject the null hypothesis and we can conclude that people under the age of forty have vocabularies that are different than those of people over sixty years of age.

6 0
2 years ago
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