Tangent this equation:
1 answer:
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We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer is
point (-5,12)
see the attached figure
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer is
point (-5,12)
see the attached figure
Answer:
- 1) 4812 students
- 2) 763 pounds
- 3) $30906.76
Step-by-step explanation:
1)
- Initial number = 2988
- Rate of increase = 10%
<u>Number of students after 6 years:</u>
2)
- Initial number = 1200
- Rate of decrease = 14%
<u>Amount of gold after 4 years:</u>
3)
- Initial number = 28000
- Rate of increase = 2.5%
a)
<u>Salary after n years:</u>
b)
<u>Salary in the 5th year:</u>