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garri49 [273]
3 years ago
10

What is the range of the function y=e4+1 graphed below?

Mathematics
1 answer:
grigory [225]3 years ago
6 0
56 I think y=e4+1 then you have to add and subtract
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Help? 2+2-8+6-2+9+5-6+6-3+8-1+7-0+8-1+10-2+11+
SOVA2 [1]

Answer:

51

Step-by-step explanation:

2+2 = 4

4 - 8 = -4

-4 + 6 = 2

2 - 2 = 0

0 + 9 = 9

9 + 5 = 14

14 - 6 = 8

8 + 6 = 14

14 - 3 = 11

11 + 8 = 19

19 - 1 = 18

18 + 7 = 25

25 - 0 = 25

25 + 8 = 33

33 - 1 = 32

32 + 10 = 42

42 - 2 = 40

40 + 11 = 51

6 0
3 years ago
A rectangle has an area of 72 in². The length and the width of the rectangle are changed by a scale factor of 3.5.
vodka [1.7K]

Answer:

882 in^2

Step-by-step explanation:

4 0
3 years ago
I am very confused please solve and explain.
e-lub [12.9K]

Answer:

c = \frac{b^2-R^2}{4a}

Step-by-step explanation:

Given

R= \sqrt{b^2-4ac}

Clear the radical by squaring both sides

R² = b² - 4ac ( subtract b² from both sides )

R² - b² = - 4ac ( multiply all terms by - 1 )

b² - R² = 4ac ( divide both sides by 4a )

\frac{b^2-R^2}{4a} = c

6 0
3 years ago
Read 2 more answers
2. Saul invested an average of $425 per month since age 30 in various securities for his
BabaBlast [244]

Answer:

$507.30

Step-by-step explanation:

-Given the monthly deposits are $425 and the interest rate is 3.5% for 30 years.

-The amount of the investment after 30 years is calculated as;

A=P(1+i/n)^n, n=time \ in \ months\\\\=425(1+0.035/12)^{30\times 12}\\\\=1212.65

-Assuming Saul started saving at age 20, his investment term will be 40 yrs.

-His investment amount is thus:

A=P(1+i/n)^n, n=time \ in \ months\\\\=425(1+0.035/12)^{40\times 12}\\\\=1719.95

#We subtract to find how much more he would have if he started saving at 20;

=A_{20}-A_{30}\\\\=1719.95-1212.65\\\\=507.30

Hence, Saul would have $507.30 more had he started saving 10 years earlier.

5 0
3 years ago
Find the least common multiple for 6(x+1)^3(x-4)^2 and 10(x+1)^8(x-4)^5
dolphi86 [110]

Answer:

30(x+1)^8 (x-4)^5

Step-by-step explanation

<h3>6(x+1)^{3}(x-4))^{2}=2X3 X (x+1)^3(x-4)^2\\10(x+1)^8(x-4)^5)= 2X5X(x+1)^8 (x-4)^5\\</h3>

In order to find the Least common multiple we write each of the factor only once from each of the expression and for the common expression we take their LCM as maximum of the exponent in  all expressions

as here in the question exponent of (x+1) are 3 and 8 so we take exponent 8

likewise for (x-4) we shall take maximum of 2 and 5 which is 5

so our expression for Least common multiple will be

2X3X5 X (x+1)^8 (x-4)^5

30(x+1)^8 (x-4)^5

7 0
3 years ago
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