Answer:
5.25
Step-by-step explanation:
The fact that the graph crosses the x-axis means the hyperbola opens to the left and right. Hence its equation is ...
x^2/a - y^2/b = 1
The point (-2, 0) helps us find "a":
(-2)^2/a - 0/b = 1
4 = a
Then we can find "b" from the other fully-specified point.
(-3)^2/4 - 4^2/b = 1 . . . . . . substitute (-3, 4) for (x, y)
b = 16/(9/4 -1) = 64/5 . . . . solve for b
Then the third point will satisfy ...
t^2/4 - (5/64)·2^2 = 1 . . . . . . substitute (t, 2) for (x, y)
t^2 = 4·(1 +5/16) = 4 +5/4 . . . . solve for t^2
t^2 = 5.25
Answer:
For 2 hours of dog stinting the total cost will be the same for the two services.
Step-by-step explanation:
x to represent the number of hours of dog sitting
<u>Derrick's Dog Sitting </u>
Fixed charged rates = $12
Sitting charges per hour = $7
⇒Charges for x hours siting = x ( Charges per hour)
= x ( $7) = 7x
⇒Total charges of Derrick's Dog Sitting for x hours = Fixed charge + Hourly Rate
= $7x + 12
<u> Darlene's Dog Sitting</u>
Fixed charged rates = $16
Sitting charges per hour = $5
⇒Charges for x hours siting = x ( Charges per hour)
= x ( $5) = 5x
⇒Total charges of Darlene's Dog Sitting<u> </u>for x hours = Fixed charge + Hourly Rate
= $5x + 16
Now, according to the question:
for x hours sitting, both company charges are same.
⇒ $7x + 12 = $5x + 16
or, 7x - 5x = 16 - 12
or, 2x = 4
⇒ x = 2
Hence, for 2 hours of dog stinting the total cost will be the same for the two services.
Answer: 7
step-by-step:
okay so first you do 7*5 which is 35 and 20+8 which is 28
then you get 35=28+x (the x is the ‘missing number’)
to find x you subtract 28 from both sides to keep the equation balanced
35-28=28-28+x
so 35-28 is 7 and 28-28 is 0 so then you have 7=x and your answer is 7
you’re doing algebra but instead of using variables your teacher is saying find the ‘missing number’ haha
