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serious [3.7K]
3 years ago
6

Help me with a algebra word problem

Mathematics
1 answer:
Alexandra [31]3 years ago
6 0
0.80m
0.50c
1.40B
0.50(8)+0.80(16)
1.40(5)-12.8(3)
31.04 should be your answer, sorry if I'm wrong! 
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The length of the rectangular basketball court is 44 feet more than the width. If the perimeter of the basketball court is 288 f
Temka [501]
Let's first say that L=W+44

and then remember that perimeter is P=2L+2W

replace the L with W+44

we then get P=2(W+44)+2W, now I'll solve it

P=2W+88+2W
P=4W+88

substitute 288 for P

288=4W+88
200=4W
50=W

so now we now how wide the court is. add 44 to find the length which gives you L=94

as always plug the numbers back into your perimeter equation to ensure L and W are correct
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3 years ago
(1,1),(-1,0)<br> 2x+y=3<br> X-2y=-1<br> Each pair of a solution of the system of linear equations
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3 years ago
24-4x=32<br><br><br> Show your work
Mandarinka [93]

Answer:

-2

Step-by-step explanation:

24 - 4x =32

-4x =32 - 24

-4x=8

x=-8 :4

x=-2

8 0
3 years ago
Read 2 more answers
I don’t really get this question can someone help me out
Inessa [10]

angles EFH and GFH are congruents

for the second equivalence criterion  two triangles are equivalents if they have  respectively  2 angles and 1 side congruents

the two triangles have congruents the angle right angle (HGF and HEF) and the 55 degrees angles (EFH and GFH); then they have in common the HF side.

so the triangles are congruent and so all the sides are respectively congruent,for example EH with HG:

EH=HG

s+36=7s

s+36-7s=0

s-7s=-36

-6s=-36

6s=36

s=6

<em>sorry for my english</em>

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3 years ago
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