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2 years ago

11.) A radioactive material has a half-life of 1 day. The material decays

Mathematics

1 answer:

Svetlanka [38]2 years ago

6 0

Answer:

UHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHHH

Step-by-step explanation:

thats what u did to me before it deleted

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How can a community be " held hostage" by a team?

mixas84 [53]

Answer:

by force I suppose

Step-by-step explanation:

how is this mathematics?

4 0

2 years ago

Read 2 more answers

A rectangle is a _____. a. quadrilateral b. square c. parallelogram d. rhombus

Pavlova-9 [17]

Both A and C is true. However, even though a rectangle can be a parallelogram, a parallelogram is a quadrilateral, so the answer is A.
I hope this helps!

8 0

3 years ago

Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth.

katrin [286]

$x=5.38$ . Correct option C)5.38

Step-by-step explanation:

Here we have , Find the value of x. O is the center of the circle. Round your answer to the nearest hundredth. picture is attached . Let's find out:

In the given figure , Let's draw a line from center to the point where cord of length 8 unit is touching the circle or intersecting or , where this chord finishes . This line is radius of circle and is denoted by x , So now we have a right angle triangle with dimensions as :

$Perpendicular =3.6\\Base=\frac{8}{2}=4\\Hypotenuse=x$

By Pythagoras Theorem ,

$Hypotenuse^2=Perpendicular^2+base^2$

⇒ $x^2=(3.6)^2+(4)^2$

⇒ $x=\sqrt{(3.6)^2+(4)^2}$

⇒ $x=\sqrt{12.96+16}$

⇒ $x=\sqrt{28.96}$

⇒ $x=5.38$

Therefore , $x=5.38$ . Correct option C)5.38

6 0

2 years ago

Please helppp with this math question <333

Naya [18.7K]

Answer:

The average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

Step-by-step explanation:

We are given the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$

We need to find average rate of change.

The formula used to find average rate of change is : $Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}$

We have b=-1 and a=-11

Finding g(b) = g(-1)

$g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9$

Finding g(a) = g(-11)

$g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29$

Finding average rate of change

$Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1$

So, the average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

5 0

2 years ago

Choose the correct subject pronoun for ' como te llama' tu ella ellos ustee

GuDViN [60]

Answer:

ustee

Step-by-step explanation:

The other ones don't make sense if you insert them into that sentence

8 0

2 years ago