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pickupchik [31]
2 years ago
14

Question in the photo Pls help

Mathematics
1 answer:
ra1l [238]2 years ago
4 0

Answer:

F = \frac{9C+160}{5}

Step-by-step explanation:

Given

C = \frac{5(F-32)}{9} ( multiply both sides by 9 to clear the fraction )

9C = 5(F - 32) ← distribute

9C = 5F - 160 ( add 160 to both sides )

9C + 160 = 5F ( divide both sides by 5 )

\frac{9C+160}{5} = F

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9.21 <br><img src="https://tex.z-dn.net/?f=9.21%20%5Cdiv%200.4%20%3D%20" id="TexFormula1" title="9.21 \div 0.4 = " alt="9.21 \di
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Let us do it by converting the 0.4 to a fraction, it has one decimal, so we'll use one zero at the denominator.

and 9.21 to a fraction as well, two decimals, thus two zeros at the denominator then,

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