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3 years ago

13

ANSWER THESE ILL GIVE U BRAINLIEST

1 answer:

Mazyrski [523]3 years ago

4 0

8 - rotation
9- rotation
10- y- axis

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N-8+n=1-4n solve for n

MrRissso [65]

Answer:

n=-N/5+9/5

Step-by-step explanation:

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4 years ago

What is 25% of 80?<br><br> ( show how u did it cause I have to write it down

Wewaii [24]

Answer:

20

Step-by-step explanation:

Write 25% as 25/100 · Since, finding the fraction of a number is same as multiplying the fraction with the number, we have 25/100 of 80 = 25/100 × 80

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2 years ago

Michael writes down 4 different factors of 60

Marizza181 [45]

Answer:

34+(-12) =22

Step-by-step explanation:

because they said that adding numbers but they didn't said that negative Or positive. so i took those numbers

3 0

3 years ago

Use the law of wines to find the value of y. Round to the nearest Tenth

Eva8 [605]

Answer:

y ≈ 2.5

Step-by-step explanation:

Using the Sine rule in Δ XYZ

$\frac{sinZ}{XY}$ = $\frac{sinY}{XZ}$ , substitute values

$\frac{sin50}{2}$ = $\frac{sin75}{y}$ ( cross- multiply )

y sin50° = 2 sin75° ( divide both sides by sin50° )

y = $\frac{2sin75}{sin50}$ ≈ 2.5 ( to the nearest tenth )

4 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

3 years ago