The answer for the question above
2 answers:
Answer:
∠ RPQ = 28°
Step-by-step explanation:
Given ∠ PRQ = 90° and ∠ SQR = 34°
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
∠ PSQ is an exterior angle of the triangle, so
∠ PSQ = 90° + 34° = 124°
Since PS = SQ then Δ PQS is isosceles and then base angles are congruent
∠ SPQ = ∠ SQP , thus
∠ RPQ = =
= 28°
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Hope this helps.
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