That's the wrong right triangle to draw. Reading the problem carefully we want this one, figure attached.
So we have the usual 30/60/90 triangle but not to scale. The sides come in ratio 1:√3:2=x:100:hypotenuse. So
x = 100/√3 ≈ 57.735
We add that to our 133.2 for the total height of the Cyclone, 190.935.
Answer: 190.9
9514 1404 393
Answer:
14. 53.1°
16. 253.7°
Step-by-step explanation:
14. The measure of angle L can be found from the cosine relation:
Cos = Adjacent/Hypotenuse
cos(L) = 9/15 = 3/5
L = arccos(3/5) = 53.1° . . . arc MK
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16. Arc MK is half of arc JK, so that arc is 106.3°. The long arc JPK is the difference between 360° and the measure of the short arc JK.
360° -106.3° = 253.7° . . . arc JPK
Answer:
a line
Step-by-step explanation:
Answer:
1. Western erodes 2 ft/yr; Dunes builds up at 5 ft/yr
2. Sometime in 2006
3. Solve simultaneous equations
Step-by-step explanation:
1. Erosion patterns
(a) Western Beach
In 15 yr, Western Beach erodes from 100 ft to 70 ft.
The rate of erosion is 30 ft/15 yr = 2 ft/yr.
(b) Dunes Beach
In 15 yr, Dunes Beach builds up from 20 ft to 95 ft.
The rate of buildup is 75 ft/15 yr = 5 ft/yr.
2. Beaches with equal width
From the table, it appears that the beaches will have the same width sometime in year 11 (2006).
3. Best approximation
The graph below also shows that it happens part way through year 11 (2006).
We could get an even better solution by calculating the equations of the two lines and solving the simultaneous equations.