I can't figure it out can you please help me
2 answers:
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Answer:
All real numbers greater than or equal to 4,999.85 millimeters and less than or equal to 5,000.15 millimeters
Step-by-step explanation:
Let
x -----> values for the center thickness of the lens
we know that
The absolute value that represent this problem is
Solve the absolute value
First case (positive)
Adds 5,000 both sides
Second case (negative)
Multiply by -1 both sides
Adds 5,000 both sides
therefore
The extreme acceptable values for the center thickness of the lens is the interval [4,999.85,5,000.15]
All real numbers greater than or equal to 4,999.85 millimeters and less than or equal to 5,000.15 millimeters