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iris [78.8K]
3 years ago
14

Solve for t: 3t + 5t - 5 = 11

Mathematics
2 answers:
seraphim [82]3 years ago
7 0

Answer:

t=2

plz mark as brainliest

Step-by-step explanation:

yuradex [85]3 years ago
3 0

Answer:

t=2 is the answer to the problem

Step-by-step explanation:

8t-5=11

8t=16

t=2

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In ΔVWX, the measure of ∠X=90°, XW = 20, WV = 29, and VX = 21. What ratio represents the cosine of ∠W?
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4. Stella says the equation x^2−8x+y^2+2y=5 has a center of (4,−1) and a radius of 5. Is she correct? Why or why not?
Ostrovityanka [42]
<h2>Stella is correct about center and wrong about radius      </h2>

Step-by-step explanation:

Equation of circle with (h,k) as center and radius r is given by,

          (x-h)²+(y-k)² = r²

Here equation is

          x²−8x+y²+2y=5

Changing in to (x-h)²+(y-k)² = r² form

           x²−8x + 16 - 16 +y²+2y+1 - 1=5  

           (x-4)² - 16 + (y+1)² -1 = 5

           (x-4)²  + (y+1)²  = 22

           (x-4)²  + (y+1)²  = 4.69²

           Center is (4,-1) and radius is 4.69

Stella is correct about center and wrong about radius            

8 0
3 years ago
Quadratic functions heeeeeellllppp
anzhelika [568]

Answer:

See below

Step-by-step explanation:

Remember that quadratic functions are parabolas when graphed.  The solutions are where the parabola crosses the x-axis.

1.   The vertex of the parabola in f(x) is (0, 9) which is above the x-axis and the parabola opens up.  So the parabola does not cross the x-axis.  Therefore the solutions are imaginary.

2.  The vertex of the parabola in g(x) is (9, 0) which is on the x-axis and parabola opens up.  Therefore, there is a double solution.

3.  The vertex of the parabola in h(x) is (-1, -9) which is below the x-axis and the parabola opens up.  Therefore, there are two real solutions.

I know this is a long explanation, but that is a way of looking at the problem.

6 0
3 years ago
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