Answer:
5a. $1.50R + $7
5b. 14 rides
Step-by-step explanation:
5b. $28 - $7= $21/1.50= 14
He can go on 14 rides
Answer:
26
Step-by-step explanation:
10+(10x3)-2(10-3)=
10+30+-2(7)=
40-14=
26
Numbers can be expressed, ordered and compared by a lot of
mathematical principles, properties, models and paradigms. There are different
properties of numbers to associate, group and distribute numbers. For example
commutative property of addition, 1 + 2 = 3 can be 3 = 1 + 2. Moreover, numbers
can be expressed by mathematical form, thus 100 wherein 1 is in the place order
of hundreds. And so on… other examples can be mathematical symbols or
inequality to compare numbers. For example, 1 > 2. One is less than 2.
Answer:The value of the bulldozer after 3 years is $121950
Step-by-step explanation:
We would apply the straight line depreciation method. In this method, the value of the asset(bulldozer) is reduced linearly over its useful life until it reaches its salvage value. The formula is expressed as
Annual depreciation expense =
(Cost of the asset - salvage value)/useful life of the asset.
From the given information,
Useful life = 23 years
Salvage value of the bulldozer = $14950
Cost of the new bulldozer is $138000
Therefore
Annual depreciation = (138000 - 14950)/ 23 = $5350
The value of the bulldozer at any point would be V. Therefore
5350 = (138000 - V)/ t
5350t = 138000 - V
V = 138000 - 5350t
The value of the bulldozer after 3 years would be
V = 138000 - 5350×3 = $121950
