Answer:
a) the varying densities are to be considered with respect to position
Step-by-step explanation:
the complete answer is found in the attachment
H=0
Therefore:
144t-16t²=0
t (144-16t)=0
We have two equations:
1)
t=0 (when the ball is released)
2)
144-16t=0
-16t=-144
t=-144 / -16=9 (this is the time )
Answer: the ball hit the ground in 9 s.
16 is correct
and so is negitive 8
The number of times the image of the octagon will coincide with the preimage during rotation is determined by:
N = R/C
where
N is the number of times the preimage coincided with the rotated image during rotation
R is the angle of rotation
C is the central angle of the regular polygon
For an octagon, the central angle is
C = 360/8 = 45
So,
N = 360 / 45 = 8
Therefore, the rotated image of the octagon will coincide with the preimage 8 times during rotation.
Answer:
12.5
Step-by-step explanation:
use a calculator and don't waste your coins
