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8090 [49]
3 years ago
12

A caterer is preparing a dinner for a party. Shecharges an initial fee of $16 and $8.25 per person. How manypeople can attend a

dinner that costs $131. 50? Write an equationand solve.
Mathematics
1 answer:
Dafna1 [17]3 years ago
7 0

Answer:

The nomber of people can attend a dinner that costs $131. 50 is 14.

Step-by-step explanation:

With the information provided, it can be said that the total cost of a dinner would be equal to the initial fee plus the result of multiplying the price per person for the number of people, which can be expressed as:

c=16+8.25x, where:

c is the total cost of he dinner

x is the number of people

Now, you can replace c with 131.50 that is the cost of a dinner and solve for x to find the number of people that can attend:

131.50=16+8.25x

131.50-16=8.25x

115.50=8.25x

x=115.50/8.25

x=14

According to this, the answer is that the nomber of people can attend a dinner that costs $131.50 is 14.

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3 years ago
Use De Moivre's theorem to write the complex number in trigonometric form: (cos(3pi/5) + i sin (3pi/5))^3
docker41 [41]

By De Moivre's theorem,

\left(\cos\dfrac{3\pi}5+i\sin\dfrac{3\pi}5\right)^3=\boxed{\cos\dfrac{9\pi}5+i\sin\dfrac{9\pi}5}

We can stop here ...

# # #

... but we can also express these trig ratios in terms of square roots. Let x=\dfrac\pi5 and let c=\cos x. Then recall that

\cos5x=c^5-10c^3\sin^2x+5c\sin^4x

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so that the answer we left in trigonometric form above is equal to

\cos\dfrac\pi5-i\sin\dfrac\pi5=\boxed{\dfrac{1+\sqrt5}4+i\sqrt{\dfrac58+\dfrac{\sqrt5}8}}

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