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babunello [35]
3 years ago
8

Help me with this please.

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
6 0

Answer: a. x^3 - x^2 + x + 3

You have to expand the terms by multiplying them.

(x^2 - 2x + 3)(x + 1)

= x^3 + x^2 - 2x^2 - 2x + 3x + 3

= x^3 - x^2 + x + 3

pogonyaev3 years ago
4 0

Answer:

option A is the correct answer of this question...

Step-by-step explanation:

x3 -2x²+3x + x²-2x +3

x³- x²+x +3

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Daily low temperatures in Columbus, OH in January 2014 were approximately normally distributed with a mean of 15.45 and a standa
Alona [7]

Answer: 12.10

Step-by-step explanation:

Given : Mean : \mu = 15.45

Standard deviation : \sigma = 13.70

The formula to calculate the z-score :-

z=\dfrac{x-\mu}{\sigma}

For x= 5 degrees

z=\dfrac{5-15.45}{13.70}=-0.7627737226\approx-0.76

For x= 10 degrees

z=\dfrac{10-15.45}{13.70}=-0.397810218\approx-0.40

The P-value : P(-0.76

=0.3445783-0.2236273=0.120951\approx0.1210

In percent , 0.1210\times100=12.10\%

Hence, the percentage of days had a low temperature between 5 degrees and 10 degrees = 12.10%

5 0
3 years ago
It takes Audrey 3/5 hour to paint 2/5 square yards of wood to be used for making shelves. How many square yards can she paint in
vlabodo [156]
First, you formulate a ratio of Audrey's work time to work done. In this case, 3/5 hour : 2/5 square yards. Expressing and simplifying that into a fraction would yield:

3/5 ÷ 2/5 = 3/5 * 5/2 = 3/2

We use this ratio to determine the sq yards she could paint in an hour:

1 hour * (1/(3/2) = 2/3 square yards

I hope I was able to help you with this question. Have a good day.
5 0
3 years ago
Read 2 more answers
The practice of buying and selling goods and services over the Internet is
Sergeu [11.5K]
A. E-Commerce, I took a tech class :)
5 0
3 years ago
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A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 3:2
alexira [117]

Answer:

B) 8:9

Step-by-step explanation:

Please refer to the attached image for explanations

4 0
3 years ago
21) Bob ran the first part of a 12 km race at a speed of 8 kmph. He ran the second part of the
diamong [38]

Answer:

Step-by-step explanation:

Bob ran the first part of a 12 km race at a speed of 8 kmph. He ran the second part of the

race at 10 kmph. If his total time for the entire race was 1.74 hours, how far did he run in

the first part of the race?

First part :

Total Distance = 12 km

First part Speed = 8kmph

Let distance covered on first part = x

Second part speed = 10kmhr

(8*x)

6 0
3 years ago
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