Answer:
which grade u r in I'm in 10th grade and Indian
Trapezoidal is involving averageing the heights
the 4 intervals are
[0,4] and [4,7.2] and [7.2,8.6] and [8.6,9]
the area of each trapezoid is (v(t1)+v(t2))/2 times width
for the first interval
the average between 0 and 0.4 is 0.2
the width is 4
4(0.2)=0.8
2nd
average between 0.4 and 1 is 0.7
width is 3.2
3.2 times 0.7=2.24
3rd
average betwen 1.0 and 1.5 is 1.25
width is 1.4
1.4 times 1.25=1.75
4th
average betwen 1.5 and 2 is 1.75
width is 0.4
0.4 times 1.74=0.7
add them all up
0.8+2.24+1.75+0.7=5.49
5.49
t=time
v(t)=speed
so the area under the curve is distance
covered 5.49 meters
Answer:
4x
Step-by-step explanation:
Answer:
(x - 7)² + (y + 2)² = (2√13)²
Step-by-step explanation:
We already know that the center is at (7, -2), but must find the radius. The radius is the distance between the points (7, -2) and (1, -6):
r = √ [6² + 4²] ) = √(36 + 16) = √52 = √4√13 = 2√13.
Then the desired equation is (x - 7)² + (y + 2)² = (2√13)²
Factor out -1
-1(x^2+x-6)
Factor the inner trinomial
-1(x+3)(x-2)
Final answer: B
