Answer:
"Teens and Distracted Driving: Texting, Talking and Other Uses of the Cell Phone Behind the Wheel"
a. The inference made involves estimation. The question provided that the statements were made on the basis of the resulting data and not on the basis of some hypothesis testing.
This implies that some statistics were calculated from sample data to approximate the population parameter, as shown in the statements. The statements were not an attempt to establish the statistical significance of some claims.
b. The population of interest is American teenagers between 12-17.
Step-by-step explanation:
An inference from data is a statistical estimation by which some statistics are calculated based on the sample data of 800 teens between the ages of 12 and 17. The statistics serve as an approximation to the population parameter.
Inference based on hypothesis testing establishes if a claim has statistical significance by providing statistical evidence in favor of the claim or against it.
The answer is C. 5c+3a=115
<span>c + a=33
</span>if each child's ticket is $3 and there are 4 child tickets sold, then the total is <span>3×4</span>
if each child ticket is $3 and there are "c" child tickets sold, the total is <span>3c</span><span> for the childs tickets </span>
Answer:
She can cut 24 ribbon from this long strip.
Step-by-step explanation:
Given that,
Bella needs identical strips of ribbon measuring 3.5 feet each.
She has 85 feet of ribbon.
3.5 feet is length of 1 ribbon.
1 feet is length of 
ribbon
85 feet is length of 
ribbon
≈24.28
7) 170(24
14
_______
30
28
______
2
So, she can cut 24 ribbon from this long strip.
From the graph, identify the x=-2 point on x axis,
(is it 2 units to left of origin.)
now, imagine a vertical line through it.
This vertical line intersects the given line at which point?
The y co-ordinate of this point is your answer.
From the given graph,
the vertical line intersects at (-2,3)
so y= 3 it is :)
Answer: The required probability is 0.004.
Step-by-step explanation:
Since we have given that
Number of pieces = 50
Number of defective pieces = 5
So, we need to draw 2 defective pieces.
So, the probability of drawing 2 defective pieces one after the other on the first and second samples would be
Hence, the required probability is 0.004.
