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Kitty [74]
3 years ago
13

A function has the ordered pairs​ (1,3), (7,4),​ (8,6), and​ (9,y). What restrictions are there on the value of y so that the in

verse of the function is also a​ function? Explain.
Mathematics
1 answer:
nordsb [41]3 years ago
4 0

Answer:

  y cannot be 3, 4, or 6

Step-by-step explanation:

If the function is to have an inverse, the y-values cannot be repeated. This means ...

  y ∉ {3, 4, 6}

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Answer:

Area of Circle A = 1133.54

Circumference of Circle A= 119.32

Step-by-step explanation:

Given: Sum of both circle diameters= 49 feet.

           Circle A radius= Three feet less than twice the diameter of circle B.

Lets assume diameter of Circle B is "x"

∴ Circle A radius (r)= (2x-3)

We know, the diameter of circle is 2r

Diameter of Circle A is 2\times (2x-3)

Next as given sum of both circle diameter is 49 feet.

∴ 2(2x-3)+x= 49\ feet

distributing 2 with 2x and -3

⇒ 4x-6+x= 49

⇒5x-6= 49

Adding both side by 6

⇒5x=55

Cross multiplying both side.

⇒x=\frac{55}{5} = 11

∴ Diameter of circle B is 11 feet.

Next, subtituting the value of x to get the value of radius for Circle A.

Radius of circle A= (2x-3)

⇒ Radius of circle A= (2\times 11-3)= 22-3

∴ Radius of circle A= 19 feet.

Area of circle= \pi r^{2}

Taking π= 3.14

Area of circle A= 3.14\times 19^{2} = 3.14\times 361

∴ Area of circle A= 1133.54

Circumference of circle= 2πr

Circumference of Circle A= 2\times 3.14\times 19= 119.32

∴ Circumference of Circle A= 119.32

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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