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Kitty [74]
3 years ago
13

A function has the ordered pairs​ (1,3), (7,4),​ (8,6), and​ (9,y). What restrictions are there on the value of y so that the in

verse of the function is also a​ function? Explain.
Mathematics
1 answer:
nordsb [41]3 years ago
4 0

Answer:

  y cannot be 3, 4, or 6

Step-by-step explanation:

If the function is to have an inverse, the y-values cannot be repeated. This means ...

  y ∉ {3, 4, 6}

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I dont understand how to do the 2x part.
kodGreya [7K]

Answer:

x=6 2/3

Step-by-step explanation:

Ratio of DEF:ABC=5/3

8*5/3=13 1/3

x=6 2/3


4 0
3 years ago
In the united states, voters who are neither democrat nor republican are called independent. it is believed that 12% of voters a
Nitella [24]

Answer:

a) 0.0245 = 2.45%

b) 0.9483 = 94.83%

c) 0.6931 = 69.31%

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are independent, or they are not. The probability of a person being independent is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

It is believed that 12% of voters are independent.

This means that p = 0.12

Survey of 29 people

This means that n = 29

a. what is the probability that none of the people are independent? probability =

This is P(X = 0). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{29,0}.(0.12)^{0}.(0.88)^{29} = 0.0245

0.0245 = 2.45% probability that none of the people are independent

b. what is the probability that fewer than 7 are independent? probability =

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{29,0}.(0.12)^{0}.(0.88)^{29} = 0.0245

P(X = 1) = C_{29,1}.(0.12)^{1}.(0.88)^{28} = 0.0971

P(X = 2) = C_{29,2}.(0.12)^{2}.(0.88)^{27} = 0.1853

P(X = 3) = C_{29,3}.(0.12)^{3}.(0.88)^{26} = 0.2274

P(X = 4) = C_{29,4}.(0.12)^{4}.(0.88)^{25} = 0.2016

P(X = 5) = C_{29,5}.(0.12)^{5}.(0.88)^{24} = 0.1374

P(X = 6) = C_{29,6}.(0.12)^{6}.(0.88)^{23} = 0.0750

P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0245 + 0.0971 + 0.1853 + 0.2274 + 0.2016 + 0.1374 + 0.0750 = 0.9483

0.9483 = 94.83% probability that fewer than 7 are independent

c. what is the probability that more than 2 people are independent? probability =

Either two or less are, or at least 3 are independent. The sum of the probabilities of these events is decimal 1. So

P(X \leq 2) + P(X > 2) = 1

We want P(X > 2). So

P(X > 2) = 1 - P(X \leq 2)

In which

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{29,0}.(0.12)^{0}.(0.88)^{29} = 0.0245

P(X = 1) = C_{29,1}.(0.12)^{1}.(0.88)^{28} = 0.0971

P(X = 2) = C_{29,2}.(0.12)^{2}.(0.88)^{27} = 0.1853

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0245 + 0.0971 + 0.1853 = 0.3069

P(X > 2) = 1 - P(X \leq 2) = 1 - 0.3069 = 0.6931

0.6931 = 69.31% probability that more than 2 people are independent

3 0
3 years ago
A market vendor sells pawpaws and guavas. In a week the number of pawpaws sold and the number of guavas sold were in the ratio 3
EastWind [94]

Total awpaws and guavas sold in a week = 328

Let the number of pawpas and guavas be x

ATQ

3x + 5x = 328

8x = 328

x = 328/8

x = 41

Pawapas in a week = 123

Guavas in a week = 205

Must click thanks and mark brainliest

3 0
3 years ago
Ty knows that 3.15 ÷ 0.25 = 12.6. Use the drop-down menus to explain how
vagabundo [1.1K]

Answer:

The first one is C. 2

The second one is A. Left

The last one is D.0.126

Step-by-step explanation:

Please give brainliest if this helps!

I hope this helps u!! :)

7 0
3 years ago
Read 2 more answers
7. Find the area of PQRS.<br> S(-4,5)<br> R(7,-1)<br> P-4,-34<br> Q(7,-9)
Alex777 [14]
Find the distance of each and then you’ll get the measurements also putting the points on the graph would help
8 0
3 years ago
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