final speed of the 3.0 kg cart is 2.67 m/s .
<u>Step-by-step explanation:</u>
Here we have , A 2.0 kg cart moving right at 5.0 on a friction less track collides with a 3.0 kg cart initially at rest. The 2.0 kg cart has a final speed of 1.0 to the left. We will use law of conservation of momentum: For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
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Therefore, final speed of the 3.0 kg cart is 2.67 m/s .
Triangle OPQ is shown below with line RS passing through points R and S:
Triangle OPQ is shown with point R lying on side OP and point S lying on side OQ Line RS is perpendicular to side OQ.
If triangle OPQ is dilated about the center of the triangle to create triangle O'P'Q', what can you conclude about segments RS and R'S'? (6 points)
Segment O'Q' is perpendicular to segment R'S'. Line RS is parallel to line R'S'. Line RS is perpendicular to line R'S'. Point P' passes through line RS.
Answer:
She had a success rate of 60 %.
Step-by-step explanation:
In order to calculate her percentage of success we need to take the total amount of shots she made and divide it by the total amounts of shots she attempted and multiply it by 100. Since she took 25 shoots and made 15, we have:
percentage of success = (15/25)*100% = 0.6*100% = 60 %
She had a success rate of 60 %.
<em>The vertex for f(x) = 1/2 x2 + 3x +3/2 is:</em>
<u><em>(-3,-3)</em></u>
(f+g)(x)=0
f (x) + g (x)=0
now,
substitute their values
x^2 -4x + x -18 = 0
x^2 -3x -18 =0
x^2 - 6x + 3x - 18 =0
x (x-6) + 3 (x-6) = 0
(x-6)(x+3) = 0
we have to find it's zeroes (or roots) now:
x-6 =0
x = 6
x +3 =0
x = -3
