Can someone help me with this: Write a word phrase that equals the equation x + 7x = 1200.

Mathematics

2 answers:

ser-zykov [4K]3 years ago

5 0

Answer:

Step-by-step explanation:

marc has x amount of money. His mom offers to give him seven times his money as a Christmas gift. when he combined, his starting money and what his mom gives him, it added up to $1200. What was marc’s starting money (x)

KengaRu [80]3 years ago

3 0

Answer:

A number plus seven times itself equals 1200.

Step-by-step explanation:

The number is "x", and 7 times itself is 7 "x". When one adds the two, they get 1200. Hence it models the situation;

x + 7x = 1200.

You might be interested in

I need help with my math homework

Klio2033 [76]

The answer should be J.15.

8 0

3 years ago

Ronald spins a spinner that has 10 sections numbered from 1 to 10. What is the probability that the spinner lands on a prime num

vladimir1956 [14]

Prime number is a whole number that has no possible divisors that 1 and itself. Prime numbers are 2, 3, 5.7.11,13,17,19,23 and 29. From 1 to 10 there are 3 prime numbers: 3,5 and 7.
The probability can be calculated as the ratio between the number of "good" events and the total number of possible events. There are three "good" events (3,5 or 7) and 10 total events, so the probability that the spinner lands on a prime number is: 3/10. So, none of the given options is true.

5 0

3 years ago

Read 2 more answers

The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c

Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 $\rm{in^3}$

Step-by-step explanation:

The linearization or linear approximation of a function $f(x)$ is given by:

$f(x_0+dx) \approx f(x_0) + df(x)|_{x_0}$ where $df$ is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh$

Taking $R_0=1.5$ inches and $h=3$ inches and evaluating the partial derivatives we obtain:

$V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh$

substituting the values and taking $dx=0.1$ and $dh=0.3$ inches we have:

$V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3} + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3} + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}$