Answer:
D, My original answer was A (-6,2) B (-6,5) but that's particular order is not an option but if you flip it you get answer D
<h3>
Answer: 29</h3>
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Work Shown:
Solve the second equation for f(b)
2f(b) = 28
f(b) = 28/2
f(b) = 14
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Plug in x = b and solve for b
f(x) = 3x-1
f(b) = 3b-1 ... replace every x with b
14 = 3b-1 ..... plug in f(b) = 14
3b-1 = 14
3b = 14+1
3b = 15
b = 15/3
b = 5
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f(x) = 3x-1
f(2b) = 3(2b)-1 .... replace every x with 2b
f(2b) = 3(2*5)-1 .... plug in b = 5
f(2b) = 3*10-1
f(2b) = 30-1
f(2b) = 29
Answer:
Bus speed: 22 mph; Trolley speed: 14 mph
Step-by-step explanation:
Let rb represent the speed of the bus and rt the speed of the trolley. Then rb = rt + 8 (mph).
Recall that distance = rate times time. Two different distances and two different speeds are involved here, but only one time.
Thus,
60 mi 44 mi
--------------------- = time (same in both cases) = -------------
rt + 8 mi/hr rt
Cross-multiplying, we get 44rt + 8(44) = 60 rt, or
352 = 16rt.
Solving this for rt, we get rt = speed of bus = 352/16 = 22 mph
The speed at which the bus travels is 22 mph and that at which the trolley travels is (22 mph - 8 mph) = 14 mph
The midpoint of those two would be (5.5, 0).
$600 / 100 = $6
$6 x 40 = $240
Answer: $240
Hope it helped :)
