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zhenek [66]
3 years ago
10

Solve the triangle using the law of cosines

Mathematics
2 answers:
charle [14.2K]3 years ago
8 0
<h2>Answer: A</h2><h2>c = 2.2in A = 57deg, B = 111deg</h2>

edg2021

zhuklara [117]3 years ago
4 0

Answer:

wich one

Step-by-step explanation:

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What is the slope of this line?
jeyben [28]

9514 1404 393

Answer:

  1/4

Step-by-step explanation:

The slope can be found using the slope formula with the two left-most marked points:

  m = (y2 -y1)/(x2 -x1)

  m = (6 -5)/(0 -(-4)) = 1/4

The slope of the line is 1/4.

6 0
3 years ago
Helpppppppppppppppppppppppppppppppppppppppppppppppppppppppppp
miv72 [106K]

Answer:

$7.56

Step-by-step explanation:

They sell it in $2.25 per kg

Hamburger: cost

      1 kg      :  2.25

      3.4       :   7.56

1 x 3.4= 3.4

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6 0
2 years ago
Which of the sums below can be expressed as 6(3 + 9)? (3 points) 18 + 54 18 + 9 9 + 15 6 + 54
vitfil [10]

6*3 = 18

6*9 = 54

so 18 +54 is the correct answer

7 0
3 years ago
Read 2 more answers
Francisca and Elizabeth are participating in a walk-a-thon fundraiser.
Ghella [55]
Francisca raises 76.50 and Elizabeth makes 43.50 together they makes 120
8 0
3 years ago
Determine if (-2,6) and (4,12) are solutions to the system of equations:
kykrilka [37]

Answer:

Both (-2,6) and (4,12) are solutions to the system.

Step-by-step explanation:

In order to determine whether the two given points represent solutions to our system of equations, we must "plug" thos points into both equations and check that the equality remains valid.

Step 1: Plug (-2,6) into y=x+8

(6) = (-2)+8 = 6

The solution verifies the equation.

Step 2: Plug (-2,6) into 2y=x^2 + 8

2(6) = (-2)^2+8=4+8=12

The solution verifies both equations. Therefore, (-2,6) is a solution to this system.

Now we must check if the second point is also valid.

Step 3: Plug (4,12) into y=x+8

(12) = (4)+8 = 12

Step 4: Plug (4,12) into 2y=x^2 + 8

2(12) = (4)^2+8=16+8=24

The solution verifies both equations. Therefore, (4,12) is another solution to this system.

3 0
3 years ago
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