1) Point-slope form
(y-y1)=m(x-x1)
m= - 3,
point (3,-4), so x1 = 3, y1 = - 4.
(y+4)= -3(x- 3)
2)Point-slope form
(y-y1)=m(x-x1)
m= - 3/4,
point (4,5), so x1 = 4, y1 = 5.
(y-5)= - 3/4(x-4)
i. Let t be the line tangent at point J. We know that a tangent line at a point on a circle, is perpendicular to the diameter comprising that certain point. So t is perpendicular to JL
let l be the tangent line through L. Then l is perpendicular to JL ii. So t and l are 2 different lines, both perpendicular to line JL.
2 lines perpendicular to a third line, are parallel to each other, so the tangents t and l are parallel to each other.
Remark. Draw a picture to check the
If we apply the distributive law to right side of the third choice we get:-
-12x - 9 = -9 - 12x
right side = left side so infinite solutions
Answer:
8.75
Step-by-step explanation:
