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Vika [28.1K]
3 years ago
11

.Joline collects hockey cards.

Mathematics
1 answer:
shusha [124]3 years ago
3 0

Answer:

25 Cards

Step-by-step explanation:

If 5 cards is 20%  and  you only need 5 more then that means you have the other 80%. So you 20 80/20 which is 4. Then do 4x5=20 then add the 5 you still need.

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Acute △ABC with angles α, β, and γ is inscribed in a circle. Tangents to the circle at points A, B, and C intersect in points M,
SOVA2 [1]

Answer:

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Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

step 1

Find the measure of arcs AB, BC and AC

we know that

The inscribed angle is half that of the arc it comprises.

so

\gamma=\frac{1}{2}[arc\ AB] ----> arc\ AB=2\gamma\\\alpha=\frac{1}{2}[arc\ BC] ----> arc\ BC=2\alpha\\\beta=\frac{1}{2}[arc\ AC] ----> arc\ AC=2\beta

step 2

Find the measure of angle M

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

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substitute

M=\frac{1}{2}[2\gamma+2\alpha-2\beta]\\M=[\gamma+\alpha-\beta]

step 3   

Find the measure of angle N

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

N=\frac{1}{2}[arc\ AC+arc\ BC-arc\ AB]

substitute

N=\frac{1}{2}[2\beta+2\alpha-2\gamma]\\N=[\beta+\alpha-\gamma]

step 4    

Find the measure of angle P

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

P=\frac{1}{2}[arc\ AC+arc\ AB-arc\ BC]

substitute

P=\frac{1}{2}[2\beta+2\gamma-2\alpha]\\P=[\beta+\gamma-\alpha]

5 0
3 years ago
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Answer:

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