Which expressions have a quotient of 3/5

Please help with this question Thank you

Elden [556K]

Answer:

4.(a) y = -2x + 5

Step-by-step explanation:

6 0

3 years ago

Show work please! this is due tmr

Varvara68 [4.7K]

Answer:

-120

Step-by-step explanation:

subtract 45 to both sides

m/8 = -15

multiply by 8 on both sides.

with the fraction just multiply by the bottom number to make m by itself.

m = -15*8

m= -120

4 0

2 years ago

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A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo

never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that $\pi = 0.08$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a p-value of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}$

$0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}$

$\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2$

$n = 996.3$

Rounding up:

A sample of 997 is needed.

3 0

3 years ago

What is the product of 2x + y and 5x – y + 3?

Radda [10]

Answer:

The product of 2x + y and 5x – y + 3 is 10x^2+ 3xy + 6x - y^2 + 3y

Step-by-step explanation:

The product of the two expressions can be expressed mathematically as;

(2x +y) (5x -y +3)

To obtain the product of these expressions, we simply expand the brackets as follows;

2x(5x -y +3) + y(5x -y +3)

= 10x^2 - 2xy + 6x + 5xy - y^2 + 3y

= 10x^2- 2xy + 5xy + 6x - y^2 + 3y

= 10x^2+ 3xy + 6x - y^2 + 3y

The product of 2x + y and 5x – y + 3 is thus 10x^2+ 3xy + 6x - y^2 + 3y

5 0

2 years ago

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Five distinct numbers are randomly distributed to players numbers 1 through 5. Whenever two playerscompare their numbers, the on

ad-work [718]

Answer:

Observe that the first and the second player have equal probability to get any of number. Using the principle of that symmetry, we have that

$P(X=0)=\frac{1}{2}$

Event X = 1 means that the first player has got greater number than the second player, but not than the third player. So, choose any three numbers out of five of them and say that the minimal number out of these three goes to the second player, mean number to the first one and the largest to the third one. Permute remaining two numbers on remaining two people. Hence

$P(X=1)=\frac{1}{6}$

Event X = 2 means that the first player has got greater number than the second and the third player, but not than the fourth player. So, choose any four numbers out of five of them and say that the minimal number and the next minimal out of these four go to the second and the third player (and permute them), third number to the first one and the largest to the fourth player. Give remaining number to the last person. Hence

$P(X=2)=\frac{1}{12}$

Event X = 3 means that the first player has got greater number than the second, the third, and the forth player, but not than the fifth player. So, permute these five numbers as follows: give the highest to the last person, the second highest to the first, and permute remaining numbers on the remaining people. Hence

$P(X=3)=\frac{1}{20}$

Event X = 4 means basically the first player has won all the battles i.e, he has got the greatest number. Hence

$P(X=4)=\frac{1}{5}$

7 0

2 years ago