A foam block is in the shape of a rectangular prism. Can a TRAPEZOID be a cross-section formed by slicing through the block? *

3(-2a-4)+3a what would this be i have so many questions today to ask y'all

Novay_Z [31]

Answer:

Solution,

$3( - 2a - 4) + 3a \\ = 3 \times ( - 2a) - 3 \times 4 + 3a \\ = - 6a - 12 + 3a \\ = - 6a + 3a - 12 \\ = - 3a - 12 \\ = - 3(a + 4)$

Hope this helps...

Good luck on your assignment...

8 0

3 years ago

Read 2 more answers

If California has 6,480 residents and each resident produces about 182 cubic feet of garbage per year, how long can the landfill

svetoff [14.1K]

Answer:

0

Step-by-step explanation:

Just 4 people per year would overflow the landfill, how would it survive 6480 people?

5 0

3 years ago

ASAP!! ILL GIVE BRAINLEST

densk [106]

Answer:

A^-1:B^-1

Step-by-step explanation:

im not 100% sure but i think this is the right answer :)

8 0

3 years ago

An ABC News poll asked adults whether they felt genetically modified food was safe to eat. 35% felt it was safe, 52% felt it was

Masteriza [31]

Answer:

The proportions differ from those reported in the survey.

Step-by-step explanation:

The Chi-square goodness of fit test would be used to determine whether the proportions differ from those reported in the survey.

The hypothesis for the test can be defined as follows:

H₀: The proportions does not differ from those reported in the survey.

Hₐ: The proportions differ from those reported in the survey.

Assume that the significance level of the test is, α = 0.01.

The Chi-square test statistic is given by:

$\chi^{2}=\sum\limits^{n}_{i=1}{\frac{(O_{i}-E_{i})^{2}}{E_{i}}}$

Consider the Excel sheet provided.

The Chi-square test statistic value is 191.32.

The p-value of the test is:

$p-value=P(\chi^{2}_{(n-1)}>191.32)\\\\=\text{CHISQ.DIST.RT}(191.32,2)\\\\=0.0000$

The p-value of the test is very small. The null hypothesis will be rejected at 1% level of significance.

Thus, concluding that the proportions differ from those reported in the survey.

5 0

3 years ago

⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden

fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = $\frac{354}{1219}$

n = sample of US adults = 1291

p = population proportion of adults

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

significance level are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]

= [ $\frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ , $\frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ ]

= [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0

3 years ago