Answer:
A non-equilateral rhombus.
Step-by-step explanation:
We can solve this graphically.
We start with square:
ABCD
with:
A = (11, - 7)
B = (9, - 4)
C = (11, - 1)
D = (13, - 4)
Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:
AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13
BC = √( (11 - 9)^2 + (-1 -(-4))^2) = √13
CD = √( (11 - 13)^2 + (-1 -(-4))^2) = √13
DA = √( (11 - 13)^2 + (-7 -(-4))^2) = √13
And we change C by C' = (11, 1)
In the image you can see the 5 points and the figure that they make:
The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.
Answer:
the answer is 240
Step-by-step explanation:
If 4% are defective, then out of a batch of 250, the number of defective is
4% x 250 = 4/100 x 250 = 10 defective
So, the number of not defective is 250 - 10 = 240 good!
Answer:
Question no.4
answer false
question no. 5
answer lifting weights
question no 6
answer doing yoga
question no 7
answer specific
question no. 8
answer true
question no. 9
answer realistic
question no. 10
true
hope I helped you :)
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Answer:
here is the answer
Step-by-step explanation:
you may please search it