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3 years ago

Need help with the problems circled in green due today!!

Mathematics

1 answer:

kherson [118]3 years ago

3 0

1. Inequality
2. No. 5+3 is equal to 8 not greater
10. 311. 13>=v-1
12. 4>= x/2.1
13. x>= 1.7
14. x<= 170
22. No
23. No
24. Yes
25a. x<8'11"
25b. No, everyone is shorter than 8'11" so no one can be 9'

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Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and 1 red marbles. Find the following probabilities of Mirand

kvasek [131]

Answer:

(a) $\frac{5}{7},\frac{1}{6}$ (b) $\frac{1}{7},\frac{1}{6}$ (c) $\frac{5}{7},\frac{2}{3},\frac{3}{5}$

Step-by-step explanation:

GIVEN: Miranda has a bag of marbles with $5$ blue marbles, $1$ white marbles, and

TO FIND: a) A Blue, then a red Preview

,b)A red, then a white Preview

,c) A Blue, then a Blue, then a Blue.

SOLUTION:

Total marbles in bag $=7$

(a)

Probability of drawing blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{5}{7}$

As marble is not returned to bag,

Probability of drawing red marble $=\frac{\text{total red marble}}{\text{total marbles}}$

$=\frac{1}{6}$

(b)

Probability of drawing red marble $=\frac{\text{total red marble}}{\text{total marbles}}$

$=\frac{1}{7}$

As marble is not returned to bag,

Probability of drawing white marble $=\frac{\text{total white marble}}{\text{total marbles}}$

$=\frac{1}{6}$

(c)

Probability of drawing blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{5}{7}$

As marble is not returned to bag,

Probability of drawing second blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{4}{6}=\frac{2}{3}$

As marble is not returned to the bag

Probability of drawing third blue marble $=\frac{\text{total blue marble}}{\text{total marbles}}$

$=\frac{3}{5}$

8 0

3 years ago

The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.

Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If $Z \leq -2$ or $Z \geq 2$ , the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1$

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{19 - 22}{1}$

$Z = -3$

$Z = -3 \leq -2$ , so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0

3 years ago

4(1 + 9x) i need assistance!

natta225 [31]

36x+4 is your answer

5 0

3 years ago

Read 2 more answers

COULD YOU GUYS HELP ME WITH 6 AND 7 PLEASE

d1i1m1o1n [39]

Answer:

Answer is given below with explanations.

Step-by-step explanation:

$type \: 1 \: MSD \: s \: appropriate \: length : \\ vessels \: equal \: to \: or \: less \: than \: \: 65 \: \\ feet \: in \: length \\ option \: a) \: is \: the \: correct \: answer. \\ type \: 2 \: MSD \: s \: appropriate \: length \\ vessels \: that \: are \: greater \: than \: 65 \: \\ feet \: in \: length. \\ note : Vessels 65 \: feet \: or less in length \\ may use a Type I, II, or III MSD. \\ Vessels more than 65 feet in length must \\ install a Type II or III MSD.$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION.

7 0

3 years ago

During one month, a homeowner used 600 units of electricity and 100 units of gas for a total cost of $344. The next month, 400 u

leonid [27]

Answer: the cost per unit of gas is $0.38

Step-by-step explanation:

Let x represent the cost per unit of electricity.

Let y represent the cost per unit of gas.

During one month, a homeowner used 600 units of electricity and 100 units of gas for a total cost of $344. It means that

600x + 100y = 344- - - - - - - - - -1

The next month, 400 units of electricity and 250 units of gas were used for a total cost of $299.

It means that

400x + 250y = 299- - - - - - - - - -1

Multiplying equation 1 by 400 and equation 2 by 600, it becomes

240000x + 40000y = 137600

240000x + 150000y = 179400

Subtracting, it becomes

- 110000y = - 41800

y = - 41800/- 110000

y = 0.38

Substituting y = 0.38 into equation 1, it becomes

600x + 100 × 0.38 = 344

600x + 38 = 344

600x = 344 - 38 = 306

x = 306/600

x = 0.51

4 0

3 years ago