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exis [7]
3 years ago
10

PLEASE HELP. i need to show my work for the correct answer. please help

Mathematics
1 answer:
e-lub [12.9K]3 years ago
7 0

Answer:

I THINK IM WRONG BUT

Step-by-step explanation:

X3 NUZZELS POINCES ON U

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Eliza is two years younger than half her brother, Juan’s age. Write an equation to represent Eliza’s age. If Juan is 6 how old i
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X = Juan's age
y = Eliza's age

Some key words/phrases we can use to help us make the equation are:

-is (whatever comes after this word usually equals the end result, or what it equals)
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just break it down :)

x/2 (half her brother's age) - 2 (two years younger) = y (Eliza is...)

| basically,
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x/2 - 2 = y
So if Juan is 6, then we need to plug in 6 for x.

6/2 - 2 = y

3 - 2 = y

1 = y

ANSWER: Eliza is one year old.
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This package of sliced cheese costs $2.97, How much would a package with 18 slices cost at the same price per slice
Mice21 [21]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
Change the following decimal numbers to percents. .25 .278 2.9 3.0 0.67
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3 0
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Read 2 more answers
Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec
o-na [289]

Answer:

(a) The probability of the event (<em>X</em> > 84) is 0.007.

(b) The probability of the event (<em>X</em> < 64) is 0.483.

Step-by-step explanation:

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 64.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...

(a)

Compute the probability of the event (<em>X</em> > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

                =1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007

Thus, the probability of the event (<em>X</em> > 84) is 0.007.

(b)

Compute the probability of the event (<em>X</em> < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

                =\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483

Thus, the probability of the event (<em>X</em> < 64) is 0.483.

5 0
3 years ago
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