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n200080 [17]
3 years ago
7

Plsss i need help with this asap !!

Mathematics
1 answer:
pashok25 [27]3 years ago
7 0
It’s cool I need help too
You might be interested in
HELP! SIMPLIFY!
Vitek1552 [10]
1)  (m³n⁵)(mn⁴)
     -----------------
      m⁻³n²

Simplify.

m⁴n⁹
-------
m⁻³n²

When the bottom power is a negative, you add it to the power on top, & when the power is a positive, you subtract it.

m⁴ + m³ = m⁷

n⁹ - n² = n⁷

So, our answer for #1 is m⁷n⁷

2)  6a²b³
     ---------
        4a

Please read rules in #1.

6 / 4 = 3/2 & a² - a = a

So, our answer is 3a
                               -----
                                 2

3)  5⁶a⁶b³
     ---------
       5²ab³
5⁶ - 5² = 5⁴ AND a⁶ - a = a⁵ AND b³-b³ = 0

So, our answer is 5⁴a⁵

Simplify 5⁴

5 × 5 × 5 × 5 = 625

So, our final answer is :

625a⁵

~Hope I helped!~
6 0
3 years ago
The Campbell family has a disposable income of $60,000 annually. Assume that their marginal propensity to consume is 0.8 (the Ca
posledela
<span>Given the Keynesian equation C=A+MD, we find 10000 + (0.8 x 60000) = $58000. M is the Marginal propensity to consume, the A is the Autonomous consumption, and D is disposable income, giving Annual consumer spending as C.</span>
7 0
3 years ago
1)
den301095 [7]
B

Subtract 2x from the left side and the right side. Then you get -y = -2x+6. The divide each side by negative 1. Thus getting you to an answer of y = 2x-6
3 0
3 years ago
Read 2 more answers
Pls help me with this problem
Luden [163]

Answer:

A is going to be 2.80

B is going to be 0.7

C points (1,0.70)

D he is buying four pounds of flour because you always put the x at the bottom and y at the top

E it will be 6.3

Step-by-step explanation:

Hope this Helped

4 0
2 years ago
Read 2 more answers
For each of the -3.3 trials, and in the same sequence in which you entered the freezing points, enter your calculated values for
dedylja [7]

Answer:

The morality of the solution is calculated as 0.859 m. We are required to determine the freezing point depression constant of pure water. The freezing point depression of the solution is given as

T_{f}  = T_{p}  -T_{s} = K_{f} * (morality of solution)

T_{p} and T_{s} are the freezing points of the pure solvent (water, 0°C) andK_{f} = freezing point depression constant of water. Therefore,

T_{f}  = K_{f} *(0.859 m)

=====> (0°C) – (3.00°C) = K_{f}  *(0.859 m)

=====> -3.00°C = K_{f}  *(0.859 m)

Ignore the negative sign (since K_{f} is positive) and get

K_{f} = (3.00°C) / (0.859 m) = 3.492°C/m

The freezing point depression constant of the solvent is 3.5°C kg/mole  

3.5 K.kg/mole (temperature differences are the same in Celsius and Kelvin scales).

3 0
3 years ago
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