Usual limit of sin is sinX/X--->1, when X--->0
sin3x/5x^3-4x=0/0?, sin3x/3x--->1 when x --->0, so sin3x/5x^3-4x= [3x. sin3x / 3x] /(5x^3-4x)=(sin3x / 3x) . (3x/5x^3-4x)
=(sin3x / 3x) . (3/5x^2- 4)
finally lim sin3x/5x^3-4x=lim (sin3x / 3x) .(3/5x^2- 4)=1x(3/-4)= - 3/4
x----->0 x---->0
Answer:
frfrfr
Step-by-step explanation:
Answer:
r = 1
Step-by-step explanation:
Solve for r
by simplifying both sides of the equation, then isolating the variable.
The answer is 240.5
Hope this helps: D
Answer:
{-1.7, 3.5}
Step-by-step explanation:
I find it convenient to graph the difference of the two sides of the equation. That difference is zero when the equation is satisfied. This equation has two solutions, near x = -1.7 and x = 3.5.
